How to replace js code in php

How to replace js code in php: 1. Create a PHP sample file; 2. Use the preg_replace regular matching function in php to replace and filter out the js code in the web page.

#The operating environment of this article: Windows 7 system, PHP version 7.1, Dell G3 computer.

How to replace js code in php?

php uses regular replacement to filter out the js (script) code

Use the preg_replace regular matching function in php to filter out the js code in the web page, preg_replace( ) represents the number of replacements. The default is -1, which means replacing all. If you only want to replace 2 times, you can write preg_replace($p1,$p2,$p3,2).

The matching rule cannot use "//i" because it cannot match newline characters, so multiple lines of js cannot be matched. Use "/<script>/i". The ? inside means as few repetitions as possible, that is, matching the nearest </script>.

Source code example:

<?php
header("Content-type:text/html;charset=utf-8");
$str = &#39;<script type="text/javascript" src="dd.js"></script>
测试php正则匹配掉js代码测试php正则匹配掉js代码测试php正则匹配掉js代码测试php正则匹配掉js代码测试php正则匹配掉js代码测试php正则匹配掉js代码
<script type="text/javascript" src="123.js"></script>
<script type="text/javascript">
var aa = "sdsds";
alert(aa);
</script>
测试php正则匹配掉js代码&#39;;
$preg = "/<script[\s\S]*?<\/script>/i";
$newstr = preg_replace($preg,"",$str,3);    //第四个参数中的3表示替换3次，默认是-1，替换全部
echo $newstr;
?>

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