PHP determines whether a number is an integer

The way PHP determines whether a number is an integer is to use the is_int function to determine and use the number to be determined as a parameter, such as [is_int($var_name1)].

The operating environment of this article: windows10 system, php 7.3, thinkpad t480 computer.

To determine whether a number is an integer is very simple in PHP. PHP has a very rich set of functions, including the is_int function, through which we can easily determine whether a number is an integer.

Let’s introduce the is_int function.

is_int() function is used to detect whether a variable is an integer. TRUE if the specified variable is an integer, FALSE otherwise.

Sample code:

<?php
$var_name1 = 678;
$var_name2 = "a678";
$var_name3 = "678";
$var_name4 = 999;
$var_name5 = 698.99;
$var_name6 = array("a1", "a2");
$var_name7 = + 125689.66;
if (is_int($var_name1)) {
    echo "$var_name1 是整数" . PHP_EOL;
} else {
    echo "$var_name1 不是整数" . PHP_EOL;
}
if (is_int($var_name2)) {
    echo "$var_name2 是整数" . PHP_EOL;
} else {
    echo "$var_name2 不是整数" . PHP_EOL;
}
$result = is_int($var_name3);
echo "[ $var_name3 是整数吗? ]" . var_dump($result) . PHP_EOL;
$result = is_int($var_name4);
echo "[ $var_name4 是整数吗? ]" . var_dump($result) . PHP_EOL;
$result = is_int($var_name5);
echo "[ $var_name5 是整数吗? ]" . var_dump($result) . PHP_EOL;
$result = is_int($var_name6);
echo "[ $var_name6 是整数吗? ]" . var_dump($result) . PHP_EOL;
$result = is_int($var_name7);
echo "[ $var_name7 是整数吗? ]" . var_dump($result);
?>

Let’s take a look at the output:

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