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How to convert json to php

藏色散人
藏色散人Original
2020-05-16 11:00:302162browse

How to convert json to php

How to convert json to php?

json_decode is a PHP built-in function added after php5.2.0. Its function is to encode strings in JSON format.

The syntax rules of json_decode:

  json_decode ( string $json [, bool $assoc = false [, int $depth = 512 [, int $options = 0 ]]] )

json_decode accepts a JSON format string and converts it into a PHP variable. When the parameter $assoc is TRUE, array will be returned, otherwise object will be returned.

String in JSON format

  $json = '{"a":"php","b":"mysql","c":3}';

Where a is the key, and php is the key value of a.

Example:

<?php   
$json = &#39;{"a":"php","b":"mysql","c":3}&#39;;  
$json_Class=json_decode($json);   
$json_Array=json_decode($json, true);   
print_r($json_Class);   
print_r($json_Array);         
?>

Program output:

  stdClass Object (
  [a] => php
  [b] => mysql
  [c] => 3 )
  Array (
  [a] => php
  [b] => mysql
  [c] => 3 )

Under the premise of the above code

Access the value of a of the object type $json_Class

echo $json_Class->{&#39;a&#39;};

Program output: php

Access the value of a in the array type $json_Array

echo $json_Array[&#39;a&#39;];

Program output: php

Related recommendations: "PHP Tutorial"

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