AJAX投票网页怎样实现返回选择页面??
我按照这个网站写的做了一个AJAX投票,并放在我的网站的主页的一个DIV里。
http://www.php100.com/manual/w3school/php/php_ajax_poll.asp.html
但是投票之后,DIV中显示投票结果之后,没有返回连接,我想在投票结果里有一个返回连接,返回到投票选项,同时页面依然不跳转。
怎么才能实现???
------解决方案--------------------
"DIV中显示投票结果之后;"
这是关键啊,备份数据,添加"返回",更新结果
------解决方案--------------------
此例中,用的是get,
返回的是html格式。
你的未返回:
是不是你的JS函数有误呢。

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