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php时间调用有关问题

WBOY
WBOYOriginal
2016-06-13 10:22:36853browse

php时间调用问题
对php编程一点不懂,请教:
想实现,*分钟前(*小时前...),不知道怎么编,在网上找到一段代码,很好用,也很简单:

PHP code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--><?php function format_time($time){       $t=time()-$time;       $f=array(           '31536000'=>'年',           '2592000'=>'个月',           '604800'=>'星期',           '86400'=>'天',           '3600'=>'小时',           '60'=>'分钟',           '1'=>'秒'      );         foreach ($f as $k=>$v)       {                   if (0 != $c=floor($t/(int)$k))           {               return $c.$v.'前';           }       }   }   echo format_time('1336880454');   ?>


但是这里时间需要转换为Unix时间戳,也找到一段代码:
PHP code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--><?php $time1 = "2012-05-13 11:40:54";$time2 = strtotime($time1);echo $time2;//转换成时间戳格式echo date('',$time2);//转换成标准日期格式?>


现在页面的代码是这样的:
PHP code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--><?php while ($row = mysql_fetch_array($rs_tmmsm)) {?>=date("Y-m-d <!--h:i-->",strtotime($row["pay_time"]))?><?php }?>


问题:想把上面三个代码整合在一起,实现我需要的,*分钟前(*小时前...),该如何搞?

------解决方案--------------------
PHP code
<?php function format_time($time){       $t=time()-$time;       $f=array(           '31536000'=>'年',           '2592000'=>'个月',           '604800'=>'星期',           '86400'=>'天',           '3600'=>'小时',           '60'=>'分钟',           '1'=>'秒'      );         foreach ($f as $k=>$v)       {                   if (0 != $c=floor($t/(int)$k))           {               return $c.$v.'前';           }       }   }  while ($row = mysql_fetch_array($rs_tmmsm)) {    echo format_time(strtotime($row["pay_time"]));}?><div class="clear">
                 
              
              
        
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