我原本的意思是如下代码
<code> $eData=array( 'section'=>$v['section'], 'page'=>$v['page'], //'status'=>$v['status'], 'type'=>$v['type'], ); unset($v['page']); //unset($v['status']); unset($v['id']); unset($v['type']); unset($v['section']); $eData['data']=serialize($v); </code>
使用闭包的方式
<code> $eData=array( 'section'=>$v['section'], 'page'=>$v['page'], //'status'=>$v['status'], 'type'=>$v['type'], 'data'=>function(){ unset($v['page']); //unset($v['status']); unset($v['id']); unset($v['type']); unset($v['section']); return serialize($v); } ); </code>
问题 1、php的闭包类closure 并不支持返回参数
问题 2、使用了use方法后仍然不能够对$v进行格式化操作,只能够删除其中的元素
use 方法
$eData=array( 'section'=>$v['section'], 'page'=>$v['page'], //'status'=>$v['status'], 'type'=>$v['type'], 'data'=>function() use($v){ unset($v['page']); //unset($v['status']); unset($v['id']); unset($v['type']); unset($v['section']); return $v=serialize($v); }, );
回复内容:
我原本的意思是如下代码
<code> $eData=array( 'section'=>$v['section'], 'page'=>$v['page'], //'status'=>$v['status'], 'type'=>$v['type'], ); unset($v['page']); //unset($v['status']); unset($v['id']); unset($v['type']); unset($v['section']); $eData['data']=serialize($v); </code>
使用闭包的方式
<code> $eData=array( 'section'=>$v['section'], 'page'=>$v['page'], //'status'=>$v['status'], 'type'=>$v['type'], 'data'=>function(){ unset($v['page']); //unset($v['status']); unset($v['id']); unset($v['type']); unset($v['section']); return serialize($v); } ); </code>
问题 1、php的闭包类closure 并不支持返回参数
问题 2、使用了use方法后仍然不能够对$v进行格式化操作,只能够删除其中的元素
use 方法
$eData=array( 'section'=>$v['section'], 'page'=>$v['page'], //'status'=>$v['status'], 'type'=>$v['type'], 'data'=>function() use($v){ unset($v['page']); //unset($v['status']); unset($v['id']); unset($v['type']); unset($v['section']); return $v=serialize($v); }, );
是要这个效果吗?
$eData = array( 'section' => $v['section'], 'page' => $v['page'], 'type' => $v['type'], 'data' => call_user_func( function() use (&$v) { unset($v['page']); unset($v['id']); unset($v['type']); unset($v['section']); return serialize($v); } ), );
大致看了一下,你应该想让 'data'是serialize($v)吧?也就是将'section','page','type'去除后后序列化的字符串吧。'data'=>function() 是将匿名函数赋给了data.不是将返回值赋给data。
第二个问题太傻叉了
'data'=>function() use($v){ unset($v['page']); //unset($v['status']); unset($v['id']); unset($v['type']); unset($v['section']); return $v=serialize($v)
使用use语法传递的是重新复制了一份传递,又不是引用,要想将$v变成序列化后的值就应该是引用use(&$v)
人家二楼说的是对的,凭什么不给人家采纳?
你那样是将一个匿名函数传给$eData['data']了,并没有把函数的返回结果给它。
不知道题主说的用闭包是怎样的情况。
就根据自己理解来回答下好了。
类似下面这样写:
<code>class A { var $eData = Array(); function formatArrayWithHookFn( $hookFn ) { $hookFn( $this->$eData ); } } $a = new A(); $a->formatArrayWithHookFn(function( $arrayToFormat ) { $arrayToFormat['foo'] = 'bar'; // ... }); </code>

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