在路由中使用
Route::controller('login', 'LoginController');
这样不走构造方法了 请问有什么解决方案
回复内容:
在路由中使用
Route::controller('login', 'LoginController');
这样不走构造方法了 请问有什么解决方案
你指的 logincontroller的构造方法么? 如果是,那是你写错方法名了吧,实例化一个类调用构造方法 是语言的特性
你的不走构造方法的描述是错误的, 肯能是走构造方法
测试方法:
在构造方法中输入
\Log::debug('some string')
, 你可以在日志中看到这个输出在构造方法中输出异常也会被框架捕捉到
构造方法不会输出的是
return, 也就是你在构造方法中使用return 是不输出任何东西的
调用类的静态函数时不会自动调用类的构造函数。 只有 new对象才会自动调用

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