Set the values ​​of map1 and map2 through reflector pointers

php editor Youzi is here to introduce a method of using reflector pointers to set the values ​​of map1 and map2. Through the reflector pointer, we can easily access and modify the properties and methods of the object to dynamically set the values ​​of map1 and map2. This approach is not only simple and easy to understand, but also provides the flexibility to change the values ​​of map1 and map2 at any time as needed. Let’s take a look at the specific steps below!

Question content

Test my sample code: https://go.dev/play/p/g7lxjdnjnan

Final Results:

&{0}
&{1}

How do I want the output from the example terminal

&{1}
&{1}

My code in the project:

func Set(recv *Value, value Value) {
    reflect.ValueOf(recv).Elem().Set(reflect.ValueOf(value))
}

func (this *SetBlock) On_Exec(locals map[string]Value) {
        //this.inputs["Recv"].Value is pointing to the same value as global
    if this.inputs["Recv"].Value != nil {
        Set(&this.inputs["Recv"].Value, this.inputs["Value"].Value.Copy())
    }
        //this.layer.Game.Globals() is a original
        fmt.Println(this.layer.Game.Globals())
    this.outputs["After"].Value = Create_Bool(true)
}

I'm here because I don't even know how to research this.

Change a and b. The person who helped me use the Settings feature sent me a code. Hope you send it too. For some reason it worked, but now it doesn't.

I cannot assign to map, Because the way this function is made I don't even know if the value is coming from an array (if it's a variable or a map label)

The "Settings" function is available for different types https://go.dev/play/p/tggxpxf5kx9

One way I'm sure would work is to create a pointer, not a map pointer, A pointer to 2 mapped values

The "set" function is based on setting a pointer to another pointer. I think the error was that I was pointing to the wrong pointer

Workaround

I envisioned that when creating the value I created two pointers to the value, i.e. ** And change in this way. Thank you: @JimB

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