How to convert string to JSON object array in php

PHP is a popular server-side programming language with a wide range of applications, especially in web development. PHP provides a rich function library and built-in data types to help developers easily manipulate different types of data. In this article, we will explore how to convert a string into an array of JSON objects.

JSON (JavaScript Object Notation) is a lightweight data format that is widely used in web applications. It uses key-value pairs to represent data, which is easy to read and use. PHP provides some functions to create and parse data in JSON format. We can use the json_encode() function to convert a PHP array into a JSON-formatted string, and the json_decode() function to decode a JSON-formatted string into a PHP array.

Let's take a look at how to convert a string into a JSON object array object. Suppose we have a string named $person, which represents personal information as follows:

$person = '{"name": "John", "age": 30, "city": "New York"}';

The string conforms to JSON format and has three attributes: name, age and city. To convert it to a JSON object, we need to use the json_decode() function as follows:

$json_person = json_decode($person);

This will convert the $person string into an object with three properties: name, age and city . Now, we can access them via:

echo $json_person->name; // 输出 John
echo $json_person->age; // 输出 30
echo $json_person->city; // 输出 New York

If we want to access the JSON object as an array, we can set the second parameter to true as follows:

$json_person = json_decode($person, true);
echo $json_person['name']; // 输出 John
echo $json_person['age']; // 输出 30
echo $json_person['city']; // 输出 New York

This will Convert the $person string into an array. The array has three key-value pairs, corresponding to the name, age and city attributes.

Now, suppose we have a string named $people, which contains multiple personal information, as shown below:

$people = '[{"name": "John", "age": 30, "city": "New York"}, {"name": "Jane", "age": 25, "city": "Los Angeles"}]';

This string conforms to JSON format, indicating that a string containing two An array of individuals. To convert it to a JSON object array object, we need to use the json_decode() function as follows:

$json_people = json_decode($people);

This will convert the $people string into an array containing two objects, each Objects have three attributes: name, age and city. Now, we can access them in the following way:

echo $json_people[0]->name; // 输出 John
echo $json_people[0]->age; // 输出 30
echo $json_people[0]->city; // 输出 New York

echo $json_people[1]->name; // 输出 Jane
echo $json_people[1]->age; // 输出 25
echo $json_people[1]->city; // 输出 Los Angeles

If we want to access the JSON object array as an array, we can set the second parameter to true as follows:

$json_people = json_decode($people, true);
echo $json_people[0]['name']; // 输出 John
echo $json_people[0]['age']; // 输出 30
echo $json_people[0]['city']; // 输出 New York

echo $json_people[1]['name']; // 输出 Jane
echo $json_people[1]['age']; // 输出 25
echo $json_people[1]['city']; // 输出 Los Angeles

This The $people string will be converted into an array, which contains two associative arrays, each array has three key-value pairs, corresponding to the name, age and city attributes respectively.

In this article, we have explored how to convert a string into an array of JSON objects. PHP provides powerful function libraries and built-in data types that allow us to easily manipulate different types of data. If you are developing web applications, these functions are one of the tools you must master.

The above is the detailed content of How to convert string to JSON object array in php. For more information, please follow other related articles on the PHP Chinese website!