How to use php to determine whether the year is a leap year

Judgment method: 1. Use the "strtotime("specified year value-02")" statement to convert the specified year date into a Unix timestamp; 2. Use "date("t", timestamp)== 29" statement obtains the number of days in February in the specified year and determines whether the number of days is equal to 29. If it is equal to 29, it is a leap year, otherwise it is not a leap year.

The operating environment of this tutorial: windows7 system, PHP7.1 version, DELL G3 computer

Use PHP to determine the year Is it a leap year?

There are 29 days in February in a leap year. We can take advantage of this feature and use date() to get the number of days contained in February in a given year $year The number of days, determine whether the number of days is 29 days, so that you can determine whether the given year $year is a leap year.

Implementation code:

<?php
header("Content-type:text/html;charset=utf-8");
function f($year) {
$time = strtotime("{$year}-02"); //取得一个日期的 Unix 时间戳;

	if (date("t", $time) == 29) {//格式化时间，并且判断2月是否是29天；
		echo $year . "是闰年!<br>";
		//是29天就输出时闰年；
	}
	else{
		echo $year . "不是闰年!<br>";
	}
}
?>

Test it:

f(2022);
f(2021);
f(2020);
f(2012);
f(2010);

##Analysis:

In the above example, the

strtotime("{$year}-02") statement converts the date in the "xxxx-02" format into a Unix timestamp; then you can use date(" t",$time) statement to get the number of days contained in February of $year. Use the if statement to determine whether the number of days is equal to 29 days, and you can determine whether $year is a leap year. The "t

" character parameter of the

date() function can be used to obtain the number of days contained in a given month. This function has many built-in characters to control the output date. Characters in string format . In fact, there is a character "L" that can be used to determine whether it is a leap year (if it is a leap year, it is 1, otherwise it is 0).

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