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This article will share with you the WeChat payment JsApi 40163 error and solution code.
Error:
Undefined array index: openid.
After inspection, it was found that: WeChat payment authorization obtains openId {"errcode":40163,"errmsg":"code been used",}
The reason is: WeChat payment code can only be used once, and it will be repeated the second time This error occurs when using.
Solving related reference: https://www.e-learn.cn/content/php/1102683
I tried the method in the reference to no avail, so I rewrote it according to the reason:
After troubleshooting, the problem was found Appears in: GetOpenid method in
WxPay.JsApiPay.php, the source code is:
/** * * 通过跳转获取用户的openid,跳转流程如下: * 1、设置自己需要调回的url及其其他参数,跳转到微信服务器https://open.weixin.qq.com/connect/oauth2/authorize * 2、微信服务处理完成之后会跳转回用户redirect_uri地址,此时会带上一些参数,如:code * * @return 用户的openid */ public function GetOpenid() { //通过code获得openid if (!isset($_GET['code']) ){ //触发微信返回code码 $baseUrl = urlencode('http://'.$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']); $url = $this->__CreateOauthUrlForCode($baseUrl); Header("Location: $url"); exit(); } else { //获取code码,以获取openid $code = $_GET['code']; $openid = $this->getOpenidFromMp($code); return $openid; } }
The modified code is:
/** * * 通过跳转获取用户的openid,跳转流程如下: * 1、设置自己需要调回的url及其其他参数,跳转到微信服务器https://open.weixin.qq.com/connect/oauth2/authorize * 2、微信服务处理完成之后会跳转回用户redirect_uri地址,此时会带上一些参数,如:code * * @return 用户的openid */ public function GetOpenid() { //通过code获得openid if (!isset($_GET['code']) ){ //触发微信返回code码 $baseUrl = urlencode('http://'.$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']); $url = $this->__CreateOauthUrlForCode($baseUrl); Header("Location: $url"); exit(); } else { //获取code码,以获取openid $code = $_GET['code']; if(session("?$code")){ $openid = $this->getOpenidFromMp($code); }else{ $openid= session($code); } session($code, $openid);// ###### 2019.03.01 加 为解决code been used return $openid; } }
The logic is to convert the obtained openid into code Save the session with the name; when requesting again, check whether the session with the name code in the request exists to prevent the code from being used twice.
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