Two ways to determine whether a variable is an integer in PHP_PHP Tutorial

The following will introduce to you two methods of using PHP to determine whether a variable is an integer. I hope this article will be helpful to you.

Method 1: You can round or round the number, and then compare it with the original number. For example, the result of floor(3.1) should be 3. In this case, obviously 3!=3.1, or you can use the ceil() function, which can also be judged. Whether the output is an integer.

Method 2: Use the function is_int() that comes with PHP to easily determine whether the number is an integer.

Example:

$a = 3.3;

//Method 1

}

The code is as follows

代码如下	复制代码
if(floor($a)==$a){  echo "$a 是整数!"; }else{  echo "$a 不是整数!"; }

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代码如下	复制代码
if(is_int($a)){  echo "$a 是整数!"; }else{  echo "$a 不是整数!"; }

if(floor($a)==$a){

echo "$a is an integer!"; }else{

代码如下	复制代码
function   str_is_int($str)   {         return   0   ===   strcmp($str   ,   (int)$str); }

echo "$a is not an integer!";

Method 2,

The code is as follows

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if(is_int($a)){ echo "$a is an integer!"; }else{ echo "$a is not an integer!"; }

Note: is_int() and floor check the type of the variable, not the content in the variable. When judging a string, you can use the following instead:

The code is as follows

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function str_is_int($str) {               return   0   ===   strcmp($str , (int)$str); } http://www.bkjia.com/PHPjc/632620.htmlwww.bkjia.comtruehttp: //www.bkjia.com/PHPjc/632620.htmlTechArticleThe following will introduce two methods for you to determine whether a variable is an integer in PHP. I hope this article will be helpful to you. Classmates will help. Method 1: You can round or round the number,...