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HomeBackend DevelopmentPHP Tutorial为什么我的表单每次刷新或者进入网站都会自动先发送一次

 















$name = isset($_POST['uname'])?$_POST['uname']:"";
$phone = isset($_POST['phone'])?$_POST['phone']:"";
$company = isset($_POST['company'])?$_POST['company']:"";
$message = isset($_POST['message'])?$_POST['message']:"";
$msg =  "name:".$name."
"."phone:".$phone."
"."company:".$company."
"."message:".$message;
$to = "long.cheng@freshds.com";
$subject = "Soriana Contact";
$from = $name;
$headers = "From: {$name}";
if(mail($to,$subject,$msg,$headers)){
echo "<script>alert('Thanks for your support')</script>";
}else{
echo "<script>alert('Failed')</script>";
return false;
}

?>

回复讨论(解决方案)

这要看你的提交判断方式

if(mail($to,$subject,$msg,$headers)){
echo "<script>alert('Thanks for your support')</script>";
}else{
echo "<script>alert('Failed')</script>";
return false;
}

这里不管你有没有值,都会跳出提示框,你并没有在这之前做个判断

这要看你的提交判断方式

if(mail($to,$subject,$msg,$headers)){
echo "<script>alert('Thanks for your support')</script>";
}else{
echo "<script>alert('Failed')</script>";
return false;
}

这里不管你有没有值,都会跳出提示框,你并没有在这之前做个判断


function formcheck(){
if(document.info.uname.value ==''||document.info.company.value ==''||document.info.phone.value ==''){
alert("The fields with * is required") ;
return false;
}

}

是这个

The fields with * is required

是弹出这个?

是直接表单发送出去了

是直接表单发送出去了

你这样写没做任务的判断,当然是直接发送出去了

if($_SERVER['REQUEST_METHOD'] != "POST") return;
你原来的 php 代码

得先做个判断先 要不然就会两次重复咯。。

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