求助一个PHP比较简单的问题
我想获取数据库受影响的行数 可是$row怎么在实现类这边获取返回影响的行数呢,新手伤不起,这个弯不会转了
<br /> <? <br /> // class_user.php <br /> class UserInfo{ <br /> private $userName; //属性,用户名 <br /> private $passWord; //属性, <br /> private $userGrade; //属性,用户级别<br /> private $row; <br /> private $userInfo; //存储数据库返回信息的数组变量. <br /> <br /> public function __construct($sql){ <br /> require_once("db_config.php"); //包含配置信息. <br /> $result= mysql_query($sql, $conn); // 执行查询语句 <br /> $this->userInfo = mysql_fetch_array($result); //返回查询结果到数组<br /> $row=mysql_num_rows($result); <br /> mysql_query("set names UTF8");<br /> mysql_close($conn); //关闭数据库连接 <br /> $this->getInfo(); //调用传递信息的方法. <br /> } <br /> // 获取信息传递给属性的方法 <br /> private function getInfo(){ <br /> <br /> $this->userName = $this->userInfo["username"]; <br /> $this->passWord = $this->userInfo["password"]; <br /> $this->userGrade = $this->userInfo["userGrade"]; <br /> } <br /> <br /> //返回每个属性的public 方法. <br /> <br /> public function getRow(){ <br /> <br /> return $this->row; <br /> } <br /> public function getUserName(){ <br /> <br /> return $this->userName; <br /> } <br /> <br /> public function getPassword(){ <br /> return $this->passWord; <br /> } <br /> <br /> <br /> public function getUserGrade(){ <br /> return$this->userGrade; <br /> } <br /> <br /> <br /> } <br /> $sql= "select * from userinfo where username='sa' ";<br /> require_once("class_user.php"); <br /> $user= new UserInfo($sql); //创建一个user对象. <br /> //书写sql<br /> $row= $user->getRow(); <br /> $username= $user->getUserName(); //分别调用方法取得数据 <br /> $password= $user->getPassword(); <br /> $usergrade= $user->getUserGrade(); <br /> <br /> echo"your name is ".$username."<br>"; //输出数据 <br /> echo"your password is ".$password."<br>"; <br /> <br /> echo"your grade is ".$usergrade."<br>"; <br /> echo"your ROW is ".$row."<br>"; <br /> ?><br /> <br />
------解决方案--------------------

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