php中怎么在外部修改类的私有或受保护属性值
在做单元测试框架时,发现了个比较郁闷的问题:测试人员需要在类外修改类的private或protected成员变量的值,而这些变量没有抽象成public的属性,同时为了代码量的问题,也不可能修改要测试的类。怎么在类外修改类的私有变量呢?请看下面的关键代码:
类文件sellAction.php, 内容如下:
<?php class SellAction{ protected $cUid; private $id; public $pId; public function output(){ echo "output protected cUid :".$this->cUid; echo "<br>"; echo "output private id :".$this->id; echo "<br>"; echo "output public pId:".$this->pId; echo "<br>"; } }
测试文件test.php,内容如下:
<?php require "sellAction.php"; function initReferenceAttr(& $reference, $arr) { if(!is_object($reference)) { throw new Exception('reference must be object'); } if(!is_array($arr)) { throw new Exception('arr must be array'); } $cls = get_class($reference); $reflectCls = new ReflectionClass ($cls); foreach($arr as $key => $val) { $pro = $reflectCls->getProperty($key); if($pro && ($pro->isPrivate() || $pro->isProtected())){ $pro->setAccessible(true); $pro->setValue($reference, $val); }else{ $reference->$key = $val; } } return true; } $act = new SellAction(); echo "not set private protect public var"; echo "<br>"; var_dump($act); $act->output(); $attr = array('cUid'=>'234556', 'pId'=>'987676757', 'id'=> '782100'); initReferenceAttr($act, $attr); echo "<br>"; print_r($attr); echo "<br>"; echo "<br>"; echo "set private protect public var "; echo "<br>"; var_dump($act); echo "<br>"; $act->output();
在浏览器中,直接浏览test.php,内容大致如下:
not set private protect public var object(SellAction)#1 (3) { ["cUid":protected]=> NULL ["id":"SellAction":private]=> NULL ["pId"]=> NULL } output protected cUid : output private id : output public pId: Array ( [cUid] => 234556 [pId] => 987676757 [id] => 782100 ) set private protect public var object(SellAction)#1 (3) { ["cUid":protected]=> string(6) "234556" ["id":"SellAction":private]=> string(6) "782100" ["pId"]=> string(9) "987676757" } output protected cUid :234556 output private id :782100 output public pId:987676757
上面的demo主要是通过反射实现该功能。反射功能需要php版本>=5.3,反射的相关信息请参阅:http://php.net/manual/en/book.reflection.php

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