PHP二分查找的疑惑
$Arr=array(1,3,4,5,7,8,9);
Search($Arr,7,0,count($Arr)-1);
function Search($Arr,$FindVal,$LeftIndex,$RightIndex){
if($FindVal>$Arr[count($Arr)-1]){
echo "找不到该值";
}else if($FindValecho "找不到该值";
}else{
$MiddleIndex=round(($LeftIndex+$RightIndex)/2);
if ($Arr[$MiddleIndex]Search($Arr,$FindVal,++$MiddleIndex,$RightIndex);
}else if($Arr[$MiddleIndex]>$FindVal){
Search($Arr,$FindVal,$LeftIndex,--$MiddleIndex);
}else{
echo "找到下标为$MiddleIndex";
}
}
}
请问下各位朋友,这段代码执行下来,是不是执行了好几个函数。有朋友能深入讲解下时序图吗? 谢谢,感激不尽。
------解决思路----------------------
$Arr = array(1,3,4,5,7,8,9);<br />Search($Arr,7,0,count($Arr)-1);<br /><br />function Search($Arr,$FindVal,$LeftIndex,$RightIndex){<br /> echo "$FindVal,$LeftIndex,$RightIndex\n"; //加上这句<br /> if($FindVal>$Arr[count($Arr)-1]){<br /> echo "找不到该值";<br /> }else if($FindVal<$Arr[0]){<br /> echo "找不到该值";<br /> }else{<br /> $MiddleIndex=round(($LeftIndex+$RightIndex)/2);<br /> if ($Arr[$MiddleIndex]<$FindVal){<br /> Search($Arr,$FindVal,++$MiddleIndex,$RightIndex);<br /> }else if($Arr[$MiddleIndex]>$FindVal){<br /> Search($Arr,$FindVal,$LeftIndex,--$MiddleIndex);<br /> }else{<br /> echo "找到下标为$MiddleIndex";<br /> }<br /> }<br />}7,0,6
7,4,6
7,4,4
找到下标为4

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