Home > Article > Backend Development > Why Does My PHP Code Always Report an Image File Exists, Even When It Doesn\'t?
Problem:
You intend to ascertain the existence of a specific image file hosted on your content delivery network (CDN). However, the code you've implemented appears to be ineffective.
Code Attempted:
<code class="php">if (file_exists(http://www.example.com/images/$filename)) { echo "The file exists"; } else { echo "The file does not exist"; }</code>
Observed Outcome:
Regardless of the image's actual existence, the code consistently reports "The file exists."
Solution:
The primary issue with the code is the absence of quotation marks around the filename variable ($filename). This variable must be enclosed in quotes to be interpreted as a string. Additionally, it is crucial to verify that $filename has undergone proper validation.
Updated Code:
<code class="php">if (file_exists('http://www.mydomain.com/images/'.$filename)) { … }</code>
Caveat:
It is crucial to note that the code will only function correctly if the allow_url_fopen setting in your PHP configuration is enabled.
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