Home >Backend Development >Golang >How to Unmarshal the Entire XML Array into a Go Struct

How to Unmarshal the Entire XML Array into a Go Struct

Barbara Streisand
Barbara StreisandOriginal
2024-10-24 06:11:30421browse

How to Unmarshal the Entire XML Array into a Go Struct

Unmarshaling XML Arrays in Go: Retrieving All Elements

When unmarshaling an XML array into a Go struct, it's possible to retrieve only the first element. To avoid this issue and obtain the entire array, follow these steps:

XML Decoding with Multiple Iterations:

Multiple XML entities reside within the XML string. To correctly unmarshal these entities, a xml.Decoder is required. Use d.Decode multiple times to retrieve each individual entity.

Example Code:

<code class="go">d := xml.NewDecoder(bytes.NewBufferString(VV))
for {
    var t HostSystemIdentificationInfo
    err := d.Decode(&t)
    if err == io.EOF { // End of file encountered
        break
    }
    if err != nil { // Handle any decoding errors
        log.Fatal(err)
    }
    fmt.Println(t) // Each element will be printed
}</code>

XML Sample:

<code class="xml"><HostSystemIdentificationInfo>
  <identifierValue>unknown</identifierValue>
  <identifierType>
    <label>Asset Tag</label>
    <summary>Asset tag of the system</summary>
    <key>AssetTag</key>
  </identifierType>
</HostSystemIdentificationInfo>
<HostSystemIdentificationInfo>
  <identifierValue>Dell System</identifierValue>
  <identifierType>
    <label>OEM specific string</label>
    <summary>OEM specific string</summary>
    <key>OemSpecificString</key>
  </identifierType>
</HostSystemIdentificationInfo></code>

By following these steps, you can successfully unmarshal the entire XML array into a Go struct, ensuring that you retrieve all elements as intended.

The above is the detailed content of How to Unmarshal the Entire XML Array into a Go Struct. For more information, please follow other related articles on the PHP Chinese website!

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn