Home >Backend Development >Python Tutorial >使用python实现拉钩网上的FizzBuzzWhizz问题示例

使用python实现拉钩网上的FizzBuzzWhizz问题示例

WBOY
WBOYOriginal
2016-06-06 11:30:501061browse

最近好多分享这个问题的代码,题目说的是用面向对象或者函数式编程,下面是PYTHON的实现示例

代码如下:


#!/usr/bin/python
#encoding:utf8

'''
The Game of "FizzBuzzWhizz"
author : wang.jiankui89@gmail.com
mobile : 130-2199-5152
'''
import sys

class teacher:
    def __init__(self, student_num):
        self.student_num = student_num

    def gameStart(self, numList):
        for i in range (1, self.student_num + 1):
            stu = student(i)
            print stu.answer(numList)

class student:
    def __init__(self, my_num):
        self.my_num = my_num

    def judgeMod(self, numList):
        modRes = ""
        for num in numList:
            if self.my_num % num == 0:
                modRes += rule[num]
        return modRes if modRes else self.my_num

    def judgeContain(self, first_num):
        conRes = ""
        if str(first_num) in str(self.my_num) :
            conRes = rule[first_num]
        return conRes

    def answer(self, numList):
        conRes = self.judgeContain(numList[0])
        return conRes if conRes else self.judgeMod(numList)

def getOps():
    '''parse options'''
    if len(sys.argv) != 4 :
        print "use as fizzBuzzWhizz.py [0-9] [0-9] [0-9]"
        sys.exit()
    else:
        first_num = int(sys.argv[1])
        second_num = int(sys.argv[2])
        third_num = int(sys.argv[3])
    return first_num, second_num, third_num

def main():
    first_num, second_num, third_num = getOps()
    global rule
    rule = {first_num:"Fizz", second_num:"Buzz", third_num:"Whizz"}

    student_num = 100

    tea = teacher(100)
    tea.gameStart( (first_num, second_num, third_num) )

if __name__ == "__main__":
    main()

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn