Home  >  Article  >  Backend Development  >  Python自定义scrapy中间模块避免重复采集的方法

Python自定义scrapy中间模块避免重复采集的方法

WBOY
WBOYOriginal
2016-06-06 11:24:211352browse

本文实例讲述了Python自定义scrapy中间模块避免重复采集的方法。分享给大家供大家参考。具体如下:

from scrapy import log
from scrapy.http import Request
from scrapy.item import BaseItem
from scrapy.utils.request import request_fingerprint
from myproject.items import MyItem
class IgnoreVisitedItems(object):
  """Middleware to ignore re-visiting item pages if they
  were already visited before. 
  The requests to be filtered by have a meta['filter_visited']
  flag enabled and optionally define an id to use 
  for identifying them, which defaults the request fingerprint,
  although you'd want to use the item id,
  if you already have it beforehand to make it more robust.
  """
  FILTER_VISITED = 'filter_visited'
  VISITED_ID = 'visited_id'
  CONTEXT_KEY = 'visited_ids'
  def process_spider_output(self, response, result, spider):
    context = getattr(spider, 'context', {})
    visited_ids = context.setdefault(self.CONTEXT_KEY, {})
    ret = []
    for x in result:
      visited = False
      if isinstance(x, Request):
        if self.FILTER_VISITED in x.meta:
          visit_id = self._visited_id(x)
          if visit_id in visited_ids:
            log.msg("Ignoring already visited: %s" % x.url,
                level=log.INFO, spider=spider)
            visited = True
      elif isinstance(x, BaseItem):
        visit_id = self._visited_id(response.request)
        if visit_id:
          visited_ids[visit_id] = True
          x['visit_id'] = visit_id
          x['visit_status'] = 'new'
      if visited:
        ret.append(MyItem(visit_id=visit_id, visit_status='old'))
      else:
        ret.append(x)
    return ret
  def _visited_id(self, request):
    return request.meta.get(self.VISITED_ID) or request_fingerprint(request)

希望本文所述对大家的Python程序设计有所帮助。

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn