What is the sum of the arrays after dividing the previous numbers?

Here, we will see an interesting question. We will take an array and find the sum by dividing each element by the previous element. Let us consider an array is {5, 6, 7, 2, 1, 4}. Then the result will be 5 (6 / 5) (7 / 6) (2 / 7) (1 / 2) (4 / 1) = 12.15238. Let's look at the algorithm for getting concepts.

Algorithm

divSum(arr, n)

begin
   sum := arr[0]
   for i := 1 to n-1, do
      sum := sum + arr[i] / arr[i-1]
   done
   return sum
end

Example

Chinese translation is:

Example

#include <iostream>
using namespace std;
float divSum(int arr[], int n){
   float sum = arr[0];
   for(int i = 1; i<n; i++){
      sum += arr[i] / float(arr[i - 1]);
   }
   return sum;
}
int main() {
   int arr[6] = {5, 6, 7, 2, 1, 4};
   int n = 6;
   cout << "Sum : " << divSum(arr, n);
}

Output

Sum : 12.1524

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