Translate the following into Chinese: Print the first k decimal places of 1/n in a C program, where n is a positive integer

Enter a number N such that 1/N will return the output generated in the form specified in decimal until the limit is reached.

It's easy to use floating point numbers, but the challenge is not to use them.

Input− n=5 k=5

Output− 20000

This means that if n=5 and k = 5 divided by 1/5 the output should be displayed to 5 decimal places. The Chinese translation of

Algorithm

Start
Step 1 -> Declare int variable n to 9 and k to 7 and remain to 1 and i
Step 2-> Loop for i to 0 and i<k and i++
   Print ((10*remain)/n)
   Remain = (10*remain)%n
Step 3-> end Loop For
Stop

Example

is:

Example

#include<stdio.h>
int main() {
   int n = 9, k = 7, remain=1,i ; // taking n for 1/n and k for decimal values
   printf("first %d digits of %d are : ",k,n);
   for(i=0;i<k;i++) {
      printf("%d",((10 * remain) / n));
      remain = (10*remain) % n;
   }
   return 0;
}

Output

If we run the above program, it will The following output is generated.

first 7 digits of 9 are : 1111111

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