


How to use Python's sort(), min(), and max() functions to sort list elements?
The sort0 method is provided in the list object, which is used to sort the elements in the original list. After sorting, the order of the elements in the original list will change.
The syntax format is as follows:
listname.sort(key=None, reverse=False)
- ##key: use Key to comparison
- reverse: Optional parameter
- False indicates ascending order
- True Indicates descending order
- Default ascending order
char.sort(key=str.lower)Note: The sort() function has general support for Chinese, and it is recommended to use other methods
The sorted() function does not change the original list and generates a new list after sorting min() function gets the specified value or the minimum value in the sequence
min(a,b,c,d)min(seq)max() function gets the specified value or The maximum value in the sequence
max(a,b,c,d)max(seq)max() function is to take the maximum value among the multiple parameters passed in, or the maximum value among the iterable object elements passed in. The default numeric parameter is the one with the larger value; the character parameter is the one with the lower alphabetical order. You can also pass in the named parameter key, which is a function used to specify the method of obtaining the maximum value. default named parameter is used to specify the default value returned when the maximum value does not exist. For example, the following code:
print(max(-1,-5,key = abs)) # 先执行abs()函数再执行max()函数 print(max(1.3,'5', key=int)) # 列表和元组 # 先比较各列表低索引值的数,如果相同,再继续比较下一个索引值的数 print(max([1,2],(1,3),key=lambda x:x[1])) array =[[1,2,3],[1,0,],[4,1,-3],[2,2,3]] print(min(array)) print(max(array)) array =[[5,2,3],[6,9,6],[5,1,8],[5,1,7]] print(min(array)) print(max(array)) 输出结果: -5 5 (1, 3) [1, 0] [4, 1, -3] [5, 1, 7] [6, 9, 6]
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