How to implement deadlock in Golang? How to avoid it?

Golang is an efficient, strongly typed, statically typed programming language developed by Google to solve problems such as deadlocks. Although it is very difficult to implement deadlock in Golang, in this article, we will explore how to implement deadlock using Golang.

What is a deadlock?

Deadlock refers to a situation where when multiple processes or threads request resources, they wait for each other, causing all processes or threads to be unable to continue executing. In high-concurrency scenarios, deadlock problems are very common.

In Golang, it is a very common way to use channels to communicate between coroutines. However, if the channel between coroutines is used improperly, it can easily lead to deadlock problems.

How to achieve deadlock?

The following code is a simple example. When two goroutines communicate with each other using channels, a deadlock problem occurs.

package main

import (
    "fmt"
)

func main() {
    fmt.Println("Start.....")
    ch := make(chan int)
    ch <p>Since the channel is used for communication between coroutines, when the channel sends or receives data, the current coroutine will be blocked. </p><p>In this code, there is a channel ch, which first sends a data 1 to the channel, and then receives the same data 1 from the channel. However, since the receiving operation of the channel must wait for the sending operation of the channel, the program will be blocked, resulting in a deadlock problem. </p><p>How to avoid deadlock? </p><p>To avoid deadlock problems, you can generally deal with them in the following ways: </p><ol>
<li>Control the order of channel sending and receiving to ensure that coroutines do not wait for each other. </li>
<li> Before using the channel, determine whether the channel has been closed. If the channel has been closed, do not send data to the channel, otherwise deadlock problems may easily occur. </li>
<li>Use the select statement to monitor multiple channels, so that you can continuously poll to avoid the problem of deadlock in the entire program due to waiting for a certain channel. </li>
</ol><p>The following is an example to avoid deadlock: </p><pre class="brush:php;toolbar:false">package main

import (
    "fmt"
)

func main() {
    fmt.Println("Start.....")
    ch := make(chan int)
    go func() {
        for {
            select {
            case v := <p>In this code, we use the select block to monitor channel ch. If there is a value in channel ch, it will be The value in the channel is received, otherwise the prompt "no value received from channel" will be output. </p><p>In this way, the program will not cause the entire program to deadlock due to waiting for a certain channel. </p><p>Summary</p><p>In Golang, although it is difficult to achieve deadlock, we can use channels reasonably, control the order of channel sending and receiving, determine whether the channel has been closed, and use Select statements are used to monitor channels and other methods to effectively avoid deadlock problems. These skills are especially important in high-concurrency scenarios. I hope readers can master these skills and apply them to actual development. </p>

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