


As a script interpretation language, Python itself is well integrated with C++, so using Python to develop and call the C/C++ underlying library where performance requirements are required is simply an artifact. This article introduces in detail the problem of Python calling C/C++ underlying libraries and passing values to each other. Let’s take a look.
Preface
Development environment:
Centos 7 + Python 3.5.1 + Qt Creator (just compiled with Qt Creator, and does not use any libraries of QT)
Python calls C/C++ libraries, there are two ways I can do it now
1.extern "C" export (It is troublesome to pass values to each other, this method is not recommended):
Make the C/C++ library the same DLL or .so as usual, for example:
//.h文件 #include <Python.h> //.cpp文件 //C/C++ my.so 或者my.dll enter "C" void printHello() { std::cout<<"Hello World"<<std::endl; }
#Python import ctypes from ctypes import * loadso = ctypes.cdll.LoadLibrary mylib = loadso("./my.so") mylib.printHello() >>>Hello world
Code explanation:
my.so There is a C export functionprintHello()
import ctypes : Import an official library, as the name suggests, it is related to C
loadso = ctypes.cdll.LoadLibrary : loadso represents the function used to load the library
mylib = loadso(“./my.so”) //Or loadso(“my.dll”) Load my.so library
mylib.printHello(): Call Library function
The above code can output normally: Hello World, but they do not pass values to each other
Python and C++ pass values to each other
//.h文件 #include <Python.h> //.cpp文件 enter "C" int printHello(const char* str) { std::cout<<str<<std::endl; return 1; }
Then the problem with Python comes
str = create_string_buffer(b"Hello World") #mylib.printHello("Hello World") 这里死活就是显示:H,*(str+4)才是'e',*(str+8) 是'l' 依次类推 print (mylib.printHello(str)) >>>Hello World >>>1 #由于对Python不是特别的熟悉 怎么也做不到显示C++返回的字符串, Python只能显示C++返回的字符串子能看到一个地址而已
2.Python extension C/C++
Not much to say, just go to the code
//.h文件 本来这是C++连接Mysql 我只摘抄部分代#include <Python.h> //.cpp文件 //传递多个参数 Python传过来的参数在args里面 PyObject* printfHello(PyObject* self,PyObject* args) { int i=0 const char* str; if (!PyArg_ParseTuple(args, "i|s", &i,&str)) //i 表示整形 s 表示字符串 return PyLong_FromLong(0); print("%d,%s",i,str); return Py_BuildValue("s","OK"); //向Python返回OK字符串 } //映射 知道MFC的一看就懂 static PyMethodDef MyMethods[] = { {"printfHello", printfHello, METH_VARARGS, //"printHello" 中可调用的函数 METH_VARARGS :带有参数 METH_NOARGS:无参数 "print"}, //说明 {"connect", connect, METH_VARARGS, "connect mysql"}, {NULL, NULL, 0, NULL} }; static PyObject* UtilError; // 向Python中注册模块 static struct PyModuleDef spammodule = { PyModuleDef_HEAD_INIT, "libMysqlUtil", //模块名字 import libMysqlUtil "C++ Connect Mysql", -1, MyMethods };//PyInit_libMysqlUtil 注意名字 一定要PyInit_ 加上你的模块名字 不然Python import 会提示没有定义 PyInit_你的模块名字 PyMODINIT_FUNC PyInit_libMysqlUtil(void) { PyObject* m = nullptr; m = PyModule_Create(&spammodule); //m= Py_InitModule(....) Python 2.7 if(!m) { return m; } UtilError = PyErr_NewException("Util.error",NULL,NULL); Py_INCREF(UtilError); PyModule_AddObject(m,"error",UtilError); return m; }
#python import libMysqlUtil libMysqlUtil.printHello(1,"hello World") >>>1,hello World >>>OK
Summary
So far, Python and C/C++ communicate with each other and can meet most needs. Structure value transfer has not been studied yet. For classes, just use pointers. , there is a pointer in C++, and the pointer is converted into an integer in Python. When Python passes this integer to C++, it uses PyArg_ParseTuple to turn the integer into a class pointer.
For more detailed explanations of how Python calls C/C++ underlying libraries and transfers values to each other, please pay attention to the PHP Chinese website!

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