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First enter the code
// 导入excel public function upload(){ $upload = new \Think\Upload();// 实例化上传类 $upload->maxSize = 3145728 ;// 设置附件上传大小 $upload->exts = array('xlsx','xls');// 设置附件上传类型 $upload->rootPath = './Uploads/'; // 设置附件上传根目录 $upload->savePath = ''; // 设置附件上传(子)目录 // 上传文件 $info = $upload->upload(); if(!$info) {// 上传错误提示错误信息 $this->error($upload->getError()); }else{// 上传成功 获取上传文件信息 foreach($info as $file){ $FilePath = $file['savePath'].$file['savename']; } dump($FilePath); } }
The page output content
string(17) "57a9841cc3208.xls"
Just the file name
I want to get the path of this file as shown below
ORZ, who can teach me
Reply content:
$upload->savePath 或 $upload->rootPath
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