Code to query search engine ranking position using PHP_PHP tutorial

Copy code The code is as follows:

/*
Query Google "Shenzhen Photography Studio", Ranking position of LANSJ; 2009-10-11
lost63.com original
Search in the first 30 pages
*/
$page=30; //Number of pages
$domain ="lansj.com"; //Domain name
//$domain="lost63.com";
for($n=0;$n<=$page;$n++){
$url ='http://www.google.cn/search?hl=zh-CN&newwindow=1&q=%E6%B7%B1%E5%9C%B3%E6%91%84%E5%BD%B1%E5%B7 %A5%E4%BD%9C%E5%AE%A4&start='.$n.'0&sa=N';
//$url='http://www.google.cn/search?hl=zh -CN&lr=&newwindow=1&q=%E8%BF%B7%E5%A4%B1%E8%B7%AF%E4%B8%8A&start='.$n.'0&sa=N';
$file=fopen ($url,"r");
while(!feof($file))
{
$result.=fgets($file,9999);
}
if(strpos ($result,$domain)==true){
echo 'Found on page '.$n.'
';
$n=$page;
}else{
echo 'Page '.$n.' not found
';
}
fclose($file);
}
?>

http://www.bkjia.com/PHPjc/321024.htmlwww.bkjia.comtruehttp: //www.bkjia.com/PHPjc/321024.htmlTechArticleCopy the code as follows: ?php /* Query the ranking position of "Shenzhen Photography Studio" on Google and LANSJ ; 2009-10-11 lost63.com original search in the first 30 pages*/ $page=30; //Number of pages $dom...