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Why can't my code jump_html/css_WEB-ITnose
- WBOYOriginal
- 2016-06-24 12:14:05895browse
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var bar=0
var line="||"
var amount="||"
count()
function count(){
bar=bar 2
amount =amount line
document.loading.chart.value=amount
document.loading.percent.value=bar "%"
if (bare3714a3d004788a1eda2610098584c9d
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de6e2b6c6b64741cdbcbc16e072e037e 如果您的浏览器不支持跳转,efb6e592ce5136d6ba16a78337adbeb17b10949939c05e150d9e13572c2ef334请点这里e6e38b3c62e8df885fe2e3986461aa635db79b134e9f6b82c0b36e0489ee08ed.94b3e26ee717c64999d7867364b1b4a3
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回复讨论(解决方案)
可以跳转的
为什么不用浏览器标准跳转呢？
<html xmlns="http://www.w3.org/1999/xhtml"><head><title>跳转中</title><meta http-equiv="refresh" content="0;url=http://www.jxy120.com"/><meta http-equiv="Content-Type" content="application/xhtml+xml;charset=utf-8"/></head><body><span>正在跳转。。。</span></p><span><a href="http://www.jxy120.com">点击直接进入</a></span><br/></body></html>
http-equiv="refresh" w3c标准，单位秒
<html xmlns="http://www.w3.org/1999/xhtml"><head><title>跳转中</title><meta http-equiv="refresh" content="1;url=http://www.jxy120.com"/><meta http-equiv="Content-Type" content="application/xhtml+xml;charset=utf-8"/></head><body><span>正在跳转。。。</span></p><span><a href="http://www.jxy120.com">点击直接进入</a></span><br/></body></html>
可以跳转的
我浏览器的事情，代码没有问题，谢了