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HomeBackend DevelopmentPHP Tutorialphp获取某个网站了内容 并且保存为TXT 下次直接从txt读取

php获取某个网站了内容 并且保存为TXT 下次直接从txt读取
file_put_contents  好像可以保存!  
具体怎么写! 不会写啊!

代码如下!

<?php function get_flash_url( $url ) { $lines = file($url); foreach ($lines as $linenum=> $line) { preg_match_all('|<title>([^<>]+)</title>|',$line,$result); $swfurl=$result[1][0]; if(!empty($swfurl)) return $swfurl; } } ?><?php $url=$_SERVER["QUERY_STRING"]; $flashurl= get_flash_url($url); echo preg_replace("/[&,?]/","",$flashurl);?>


回复讨论(解决方案)

这个取得了flash的路径 完后你要把路径给写到一个text内?


。。写个完整的拉啊! 不会啊!

你是要将
echo preg_replace("/[&,?]/","",$flashurl);
的结果写到文件里吗?
$s = preg_replace("/[&,?]/","",$flashurl);
file_put_contents('文件名.txt', $s);


回复楼上
  : 
我想   
$s = preg_replace("/[&,?]/","",$flashurl);  //这获取结果  
file_put_contents('news.txt', $s);/ /然后 保存 到txt 里  这里!缓存
//  因为 获取内容 很多!  flashurl如果 获取了 一个 news.txt保存了下来  flashurl在 获取其他的内容  之前保存的会 被 覆盖了!news.txt 里的内容  这个我测试过!  
//    保存下来之后! http://bbs.csdn.net/1.php?http://bbs.csdn.net/topics/
比如这样!  内容保存下来了! 在次访问这个地址的时候! 不在 http://bbs.csdn.net/topics/ 这获取内容  直接重 news.txt保存下来的内容里获取!  
 

//  因为 获取内容 很多!  flashurl如果 获取了 一个 news.txt保存了下来  flashurl在 获取其他的内容  之前保存的会 被 覆盖了!news.txt 里的内容  这个我测试过!   这个 怎么解决  把  没个获取下来的数据都保存到一个txt  或者 超过 几MB后! 重新生成 文件 news.txt  news2.txt  这样!  要把没个地址 获取下来的内容都保存!  然后下次 在访问 同一个  地址的时候! 保存下来之后! http://bbs.csdn.net/1.php?http://bbs.csdn.net/topics/
比如这样!  内容保存下来了! 在次访问这个地址的时候! 不在 http://bbs.csdn.net/topics/ 这获取内容  直接重 news.txt保存下来的内容里获取!  


不是有追加方式吗?
你只要认真看一下 file_pu_contents 函数的说明,你的疑问就不复存在了

真正需要思考的是:当多组数据存放在一个文件中时,你如何把他们分开

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