Home >Backend Development >Golang >How Can I Efficiently Initialize Arrays in Go, Similar to C 's memset?
Is there an Equivalent of memset in Go?
In C , the memset function allows for the efficient initialization of arrays with specific values. In Go, while there is no direct equivalent, several techniques can achieve similar results.
Loop Iteration
The simplest approach is to use a loop to set each element of an array to the desired value.
func memsetLoop(a []int, v int) { for i := range a { a[i] = v } }
Repeated copy()
Taking advantage of the highly optimized copy() function, we can leverage a repeated copy pattern to efficiently set array values.
func memsetRepeat(a []int, v int) { if len(a) == 0 { return } a[0] = v for bp := 1; bp < len(a); bp *= 2 { copy(a[bp:], a[:bp]) } }
Benchmark Results
To assess the performance of these techniques, we benchmark them against each other for different array sizes.
var a = make([]int, 1000) // Size will vary func BenchmarkLoop(b *testing.B) { for i := 0; i < b.N; i++ { memsetLoop(a, 10) } } func BenchmarkRepeat(b *testing.B) { for i := 0; i < b.N; i++ { memsetRepeat(a, 11) } }
The results show that memsetRepeat() outperforms memsetLoop() for larger arrays, demonstrating its efficiency for fast initialization.
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