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How to Implement IF-THEN-ELSE Logic in Spark DataFrames?

Mary-Kate Olsen
Mary-Kate OlsenOriginal
2024-11-17 04:18:03258browse

How to Implement IF-THEN-ELSE Logic in Spark DataFrames?

Spark Equivalent of IF Then ELSE

This question delves into creating a new column in a Spark DataFrame based on conditional rules.

Issue with When Function

The provided code attempts to use the when() function to create a new column named "Class" based on the values in the "iris_class" column. However, it throws an error stating that when() takes only two arguments.

Correct Syntax and Structure

The correct syntax for the when() function is:

F.when(condition1, value1).when(condition2, value2)...otherwise(otherwiseValue)

This allows for multiple when() clauses to be chained together, with an optional otherwise() clause to handle cases not covered by the when() clauses.

The equivalent SQL for this syntax would be a CASE statement with multiple WHEN clauses, as shown below:

CASE
    WHEN condition1 THEN value1
    WHEN condition2 THEN value2
    ...
    ELSE otherwiseValue
END

Recommended Solution

Therefore, the correct code to create the "Class" column should be:

iris_spark_df = iris_spark.withColumn(
    "Class", 
    F.when(iris_spark.iris_class == 'Iris-setosa', 0)
    .when(iris_spark.iris_class == 'Iris-versicolor', 1)
    .otherwise(2)
)

Alternative Syntax

Another valid syntax for achieving the same result is:

iris_spark_df = iris_spark.withColumn(
    "Class", 
    F.when(iris_spark.iris_class == 'Iris-setosa', 0)
    .otherwise(
        F.when(iris_spark.iris_class == 'Iris-versicolor', 1)
        .otherwise(2)
    )
)

Note on Hive IF

It's important to note that the Hive IF conditional, which has the syntax IF(condition, if-true, if-false), is not supported in Spark. This conditional can only be used in raw SQL queries with Hive support.

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