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Extracting Double Values from Strings Using Regex
Problem: How can you isolate a double value from a string using a regular expression?
Consider the following code snippet:
<code class="python">import re pattr = re.compile(???) x = pattr.match("4.5")</code>
Solution:
To extract a double value from a string using a regular expression, you can use the following regular expression:
(?x) ^ [+-]?\ * # Optional sign and space ( # Integers or f.p. mantissas: \d+ # Integers of the form a... ( \.\d* # Mantissa of the form a.b or a. )? # ? takes care of integers of the form a |\.\d+ # Mantissa of the form .b ) ([eE][+-]?\d+)? # Optionally match an exponent $
This regular expression matches strings that start with an optional sign and space, followed by an integer or floating-point mantissa, and an optional exponent.
Here's an example:
<code class="python">import re re_float = re.compile("""(?x) ^ [+-]?\ * # Optional sign and space ( # Integers or f.p. mantissas: \d+ # Integers of the form a... ( \.\d* # Mantissa of the form a.b or a. )? # ? takes care of integers of the form a |\.\d+ # Mantissa of the form .b ) ([eE][+-]?\d+)? # Optionally match an exponent $""") m = re_float.match("4.5") print(m.group(0)) # -> 4.5</code>
Extracting Multiple Numbers from a String:
If you need to extract multiple numbers from a larger string, you can use the findall() function:
<code class="python">s = """4.5 abc -4.5 abc - 4.5 abc + .1e10 abc . abc 1.01e-2 abc 1.01e-.2 abc 123 abc .123""" print(re.findall(r"[+-]? *(?:\d+(?:\.\d*)?|\.\d+)(?:[eE][+-]?\d+)?", s)) # -> ['4.5', '-4.5', '- 4.5', '+ .1e10', ' 1.01e-2', # ' 1.01', '-.2', ' 123', ' .123']</code>
This regular expression will match any number that consists of an optional sign, space, a combination of integer and optional fractional part, and an optional exponent notation.
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