


Extracting Double Values from Strings Using Regex
Problem: How can you isolate a double value from a string using a regular expression?
Consider the following code snippet:
<code class="python">import re pattr = re.compile(???) x = pattr.match("4.5")</code>
Solution:
To extract a double value from a string using a regular expression, you can use the following regular expression:
(?x) ^ [+-]?\ * # Optional sign and space ( # Integers or f.p. mantissas: \d+ # Integers of the form a... ( \.\d* # Mantissa of the form a.b or a. )? # ? takes care of integers of the form a |\.\d+ # Mantissa of the form .b ) ([eE][+-]?\d+)? # Optionally match an exponent $
This regular expression matches strings that start with an optional sign and space, followed by an integer or floating-point mantissa, and an optional exponent.
Here's an example:
<code class="python">import re re_float = re.compile("""(?x) ^ [+-]?\ * # Optional sign and space ( # Integers or f.p. mantissas: \d+ # Integers of the form a... ( \.\d* # Mantissa of the form a.b or a. )? # ? takes care of integers of the form a |\.\d+ # Mantissa of the form .b ) ([eE][+-]?\d+)? # Optionally match an exponent $""") m = re_float.match("4.5") print(m.group(0)) # -> 4.5</code>
Extracting Multiple Numbers from a String:
If you need to extract multiple numbers from a larger string, you can use the findall() function:
<code class="python">s = """4.5 abc -4.5 abc - 4.5 abc + .1e10 abc . abc 1.01e-2 abc 1.01e-.2 abc 123 abc .123""" print(re.findall(r"[+-]? *(?:\d+(?:\.\d*)?|\.\d+)(?:[eE][+-]?\d+)?", s)) # -> ['4.5', '-4.5', '- 4.5', '+ .1e10', ' 1.01e-2', # ' 1.01', '-.2', ' 123', ' .123']</code>
This regular expression will match any number that consists of an optional sign, space, a combination of integer and optional fractional part, and an optional exponent notation.
The above is the detailed content of How to Extract Double Values from Strings Using Regular Expressions?. For more information, please follow other related articles on the PHP Chinese website!

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