提交的数据
<code>$_GET = [ 'r' => 'site/login', ]; $_POST = [ '_csrf' => 'WjgxM0tfa3YxQn1rcg4vHioLVlt.EjhOAnFVR3MuXgQ7WkNmBwofIg==', 'LoginForm' => [ 'username' => 'admin', 'password' => 'admin', 'rememberMe' => '1', ], 'login-button' => '', ]; </code>
yii2 处理管理员登陆部分的代码:
#/var/www/example.com/public_html/yii/backend/controllers/SiteController.php public function actionLogin() { if (!\Yii::$app->user->isGuest) { return $this->goHome(); } $model = new LoginForm(); if ($model->load(Yii::$app->request->post()) && $model->login()) { return $this->goBack(); } else { return $this->render('login', [ 'model' => $model, ]); } }
但是我并没有user表,这里是backend,管理员登陆部分,对应的表是admin,结构。
<br>mysql> desc admin; +-------+------------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-------+------------------+------+-----+---------+-------+ | id | int(10) unsigned | NO | | NULL | | | name | char(30) | NO | | | | | pwd | char(32) | NO | | | | | email | char(30) | NO | | | | +-------+------------------+------+-----+---------+-------+ 4 rows in set (0.03 sec) mysql> select * from admin; +----+---------+----------------------------------+-------+ | id | name | pwd | email | +----+---------+----------------------------------+-------+ | 1 | admin | b9840270f7f4ed699ccc93cc09914d21 | | +----+---------+----------------------------------+-------+ 1 row in set (0.00 sec)
yii2 他默认的都是user表,可我并没有user表。
我现在提交了用户名和密码,该如何修改actionLogin里面的代码才最合适。
回复内容:
提交的数据
<code>$_GET = [ 'r' => 'site/login', ]; $_POST = [ '_csrf' => 'WjgxM0tfa3YxQn1rcg4vHioLVlt.EjhOAnFVR3MuXgQ7WkNmBwofIg==', 'LoginForm' => [ 'username' => 'admin', 'password' => 'admin', 'rememberMe' => '1', ], 'login-button' => '', ]; </code>
yii2 处理管理员登陆部分的代码:
#/var/www/example.com/public_html/yii/backend/controllers/SiteController.php public function actionLogin() { if (!\Yii::$app->user->isGuest) { return $this->goHome(); } $model = new LoginForm(); if ($model->load(Yii::$app->request->post()) && $model->login()) { return $this->goBack(); } else { return $this->render('login', [ 'model' => $model, ]); } }
但是我并没有user表,这里是backend,管理员登陆部分,对应的表是admin,结构。
<br>mysql> desc admin; +-------+------------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-------+------------------+------+-----+---------+-------+ | id | int(10) unsigned | NO | | NULL | | | name | char(30) | NO | | | | | pwd | char(32) | NO | | | | | email | char(30) | NO | | | | +-------+------------------+------+-----+---------+-------+ 4 rows in set (0.03 sec) mysql> select * from admin; +----+---------+----------------------------------+-------+ | id | name | pwd | email | +----+---------+----------------------------------+-------+ | 1 | admin | b9840270f7f4ed699ccc93cc09914d21 | | +----+---------+----------------------------------+-------+ 1 row in set (0.00 sec)
yii2 他默认的都是user表,可我并没有user表。
我现在提交了用户名和密码,该如何修改actionLogin里面的代码才最合适。
1 参考高级模板里里的common\models\User 修改 Admin, 并改成目前的密码加密方式.
2 修改 配置文件里的
<code>'user' => [ // 'identityClass' => 'common\models\User', 'identityClass' => 'common\models\Admin', 'enableAutoLogin' => true, ], </code>
- 修改LoginForm getUser() 从您的用户表获取用户.
试了一下2.0, 把models/User.php
修改成下边这样.
<?php namespace app\models; //继承关系修改为如下 class User extends \yii\db\ActiveRecord implements \yii\web\IdentityInterface { public $id; //username字段修改为name public $name; //password字段修改为pwd public $pwd; public $authKey; public $accessToken; public static function tableName() { //数据库表名修改user为admin return '{{admin}}'; } public static function findIdentity($id) { return static::findOne($id); } public static function findIdentityByAccessToken($token) { return static::findOne(['access_token' => $token]); } public static function findByUsername($username) { //username修改为name return static::findOne(['name' => $username]); } public function getId() { return $this->id; } public function getAuthKey() { return $this->authKey; } public function validateAuthKey($authKey) { return $this->authKey === $authKey; } public function validatePassword($password) { //password修改为pwd return $this->pwd === $password; } }
你应该增加一个UserIdentity 并且修改LoginForm 两者结合才可以不用父类的User表
很简单,添加权限管理,快捷方便。你可以去看官方文档中的rbac的角色管理一章。建议:后台管理员和普通用户放在一块。这样才有高级程序员的范!

Reasons for PHPSession failure include configuration errors, cookie issues, and session expiration. 1. Configuration error: Check and set the correct session.save_path. 2.Cookie problem: Make sure the cookie is set correctly. 3.Session expires: Adjust session.gc_maxlifetime value to extend session time.

Methods to debug session problems in PHP include: 1. Check whether the session is started correctly; 2. Verify the delivery of the session ID; 3. Check the storage and reading of session data; 4. Check the server configuration. By outputting session ID and data, viewing session file content, etc., you can effectively diagnose and solve session-related problems.

Multiple calls to session_start() will result in warning messages and possible data overwrites. 1) PHP will issue a warning, prompting that the session has been started. 2) It may cause unexpected overwriting of session data. 3) Use session_status() to check the session status to avoid repeated calls.

Configuring the session lifecycle in PHP can be achieved by setting session.gc_maxlifetime and session.cookie_lifetime. 1) session.gc_maxlifetime controls the survival time of server-side session data, 2) session.cookie_lifetime controls the life cycle of client cookies. When set to 0, the cookie expires when the browser is closed.

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Implementing custom session processing in PHP can be done by implementing the SessionHandlerInterface interface. The specific steps include: 1) Creating a class that implements SessionHandlerInterface, such as CustomSessionHandler; 2) Rewriting methods in the interface (such as open, close, read, write, destroy, gc) to define the life cycle and storage method of session data; 3) Register a custom session processor in a PHP script and start the session. This allows data to be stored in media such as MySQL and Redis to improve performance, security and scalability.

SessionID is a mechanism used in web applications to track user session status. 1. It is a randomly generated string used to maintain user's identity information during multiple interactions between the user and the server. 2. The server generates and sends it to the client through cookies or URL parameters to help identify and associate these requests in multiple requests of the user. 3. Generation usually uses random algorithms to ensure uniqueness and unpredictability. 4. In actual development, in-memory databases such as Redis can be used to store session data to improve performance and security.

Managing sessions in stateless environments such as APIs can be achieved by using JWT or cookies. 1. JWT is suitable for statelessness and scalability, but it is large in size when it comes to big data. 2.Cookies are more traditional and easy to implement, but they need to be configured with caution to ensure security.


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