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文字

返回值:String

jQuery.param(obj,[traditional])

概述

将表单元素数组或者对象序列化。是.serialize()的核心方法。

在jQuery 1.3中,如果传递的参数是一个函数,那么用.param()会得到这个函数的返回值,而不是把这个函数作为一个字符串来返回。

在jQuery 1.4中,.param()会深度递归一个对象来满足现在脚本语言和框架,比如PHP, Ruby on Rails等。你可以通过jQuery.ajaxSettings.traditional = true; 来全局得禁用这个功能。

注意:因为有些框架在解析序列化数字的时候能力有限,所以当传递一些含有嵌套对象、数组的对象作为参数时,请务必小心!

在jQuery 1.4中,HTML5的input元素也会被序列化。

参数

objArray<Elements>/jQuery/ObjectV1.2

数组或jQuery对象会按照name/value对进行序列化,普通对象按照key/value对进行序列化。

obj,[traditional]Array<Elements>/jQuery/Object,BooleanV1.4

obj:数组或jQuery对象会按照name/value对进行序列化,普通对象按照key/value对进行序列化。

traditional:是否使用传统的方式浅层序列化。

示例

描述:

按照key/value对序列化普通对象。

jQuery 代码:
    var params = { width:1680, height:1050 };
    var str = jQuery.param(params);
    $("#results").text(str);
结果:
width=1680&height=1050

描述:

对比两种序列化方式

jQuery 代码:
var myObject = {
  a: {
    one: 1, 
    two: 2, 
    three: 3
  }, 
  b: [1,2,3]
};
var recursiveEncoded = $.param(myObject);
var recursiveDecoded = decodeURIComponent($.param(myObject));

alert(recursiveEncoded);
alert(recursiveDecoded);
//a%5Bone%5D=1&a%5Btwo%5D=2&a%5Bthree%5D=3&b%5B%5D=1&b%5B%5D=2&b%5B%5D=3
//a[one]=1&a[two]=2&a[three]=3&b[]=1&b[]=2&b[]=3

var shallowEncoded = $.param(myObject, true);
var shallowDecoded = decodeURIComponent(shallowEncoded);

alert(shallowEncoded);
alert(shallowDecoded);
//a=%5Bobject+Object%5D&b=1&b=2&b=3
//a=[object+Object]&b=1&b=2&b=3


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