Home  >  Article  >  Backend Development  >  python生成日历实例解析

python生成日历实例解析

WBOY
WBOYOriginal
2016-06-06 11:31:571247browse

本文实例展示了Python生成日历的实现方法。该实例可实现一个月的日历生成5x7的列表,列表里的没个日期为datetime类型,采用python自带的 calendar 模块实现。

程序运行结果如下:

python test.py 2014 09 
2014-08-31 2014-09-01 2014-09-02 2014-09-03 2014-09-04 2014-09-05 2014-09-06 
2014-09-07 2014-09-08 2014-09-09 2014-09-10 2014-09-11 2014-09-12 2014-09-13 
2014-09-14 2014-09-15 2014-09-16 2014-09-17 2014-09-18 2014-09-19 2014-09-20 
2014-09-21 2014-09-22 2014-09-23 2014-09-24 2014-09-25 2014-09-26 2014-09-27 
2014-09-28 2014-09-29 2014-09-30 2014-10-01 2014-10-02 2014-10-03 2014-10-04 

python代码如下:

#coding:utf-8
# Last modified: 2014-08-21 11:08:08 
import calendar 
import datetime 
import sys 
 
def getcal(y, m): 
 # 从周日开始 
 cal = calendar.Calendar(6) 
 if not isinstance(y, int): y = int(y) 
 if not isinstance(m, int): m = int(m) 
 if m == 1: # 1月份 
  py = y - 1; pm = 12; 
  ny = y; nm = 2 
 elif m == 12: # 12月份 
  py = y; pm = 11 
  ny = y + 1; nm = 1 
 else: 
  py = y; pm = m - 1 
  ny = y; nm = m + 1 
 pcal = cal.monthdayscalendar(py, pm) # 上一月 
 ncal = cal.monthdayscalendar(ny, nm) # 下一月 
 ccal = cal.monthdayscalendar(y, m)  # 当前 
 w1 = ccal.pop(0) # 取第一周 
 w2 = ccal.pop() # 取最后一周 
 wp = pcal.pop() # 上个月的最后一周 
 wn = ncal.pop(0) # 下个月的第一周 
 #r1 = [datetime.date(y, m ,w1[i]) or wp[i] for i in range(7)] 
 r1 = [w1[i] and datetime.date(y, m, w1[i]) or datetime.date(py, pm, wp[i]) for i in range(7)] 
 r2 = [w2[i] and datetime.date(y, m, w2[i]) or datetime.date(ny, nm, wn[i]) for i in range(7)] 
 # 转datetime 
 result = [] 
 result.append(r1) # 第一周 
 for c in ccal:  # 其他周 
  result.append([datetime.date(y,m,i) for i in c]) 
 result.append(r2) # 最后一周 
 return result 
 
if __name__ == '__main__': 
 for w in getcal(sys.argv[1], sys.argv[2]): 
  for d in w: 
   print d, 
  print 

希望本文所述实例对大家的Python程序设计有所帮助。

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn