What does a* mean in c++

In C, a* represents the address pointing to variable a. It returns the memory location where the variable is stored and is used for passing addresses, dynamic memory allocation, and accessing array elements.

The meaning of a* in C

Answer: a* in C means pointing The address of variable a.

Detailed explanation:

a* operator is a unary operator that returns the address stored in variable a. An address is a memory location that represents the location of a variable in computer memory.

• For integer variables, the address is the memory location where the actual value of the variable is stored.
• For object variables, the address is the memory location where the object pointer is stored, which points to the actual location of the object.

Usage:

a* operator is mainly used for the following purposes:

• Pass the address of a variable as a function parameter.
• Dynamic memory allocation (for example, using new).
• Access array elements (for example, arr[i] is equivalent to *(arr i)).

Example:

<code class="cpp">int main() {
  int a = 10;
  int *ptr = &a;  // ptr 存储变量 a 的地址

  cout << "地址: " << &a << endl;
  cout << "地址 (通过指针): " << ptr << endl;
  cout << "值 (通过地址): " << *ptr << endl;

  return 0;
}</code>

Output:

<code>地址: 0x7ffe5c053140
地址 (通过指针): 0x7ffe5c053140
值 (通过地址): 10</code>

In the example, &a and *ptr store the same address which points to the storage The actual value of variable a.

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