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理解NULL如何影响IN和EXITS语句_MySQL

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2016-06-01 13:56:191076browse

从表面上看,IN和EXITS的SQL语句是可互换和等效的。然而,它们在处理UULL数据时会有很大的差别,并导致不同的结果。问题的根源是在一个Oracle数据库中,一个NULL值意味着未知变量,所以操作NULL值的比较函数的结果也是一个未知变量,而且任何返回NULL的值通常也被忽略。例如,以下查询都不会返回一行的值:

select 'true' from dual where 1 = null;

select 'true' from dual where 1 != null;

只有IS NULL才能返回true,并返回一行:

select 'true' from dual where 1 is null;

select 'true' from dual where null is null;

当你选择使用IN,你将会告诉SQL选择一个值并与其它每一值相比较。如果NULL值存在,将不会返回一行,即使两个都为NULL。

select 'true' from dual where null in (null);

select 'true' from dual where (null,null) in ((null,null));

select 'true' from dual where (1,null) in ((1,null));

一个IN语句在功能上相当于= ANY语句:

select 'true' from dual where null = ANY (null);

select 'true' from dual where (null,null) = ANY ((null,null));

select 'true' from dual where (1,null) = ANY ((1,null));

当你使用一个EXISTS等效形式的语句,SQL将会计算所有行,并忽略子查询中的值。

select 'true' from dual where exists (select null from dual);

select 'true' from dual where exists (select 0 from dual where null is null);

IN和EXISTS在逻辑上是相同的。IN语句比较由子查询返回的值,并在输出查询中过滤某些行。EXISTS语句比较行的值,并在子查询中过滤某些行。对于NULL值的情况,行的结果是相同的。

selectename from emp where empno in (select mgr from emp);

selectename from emp e where exists (select 0 from emp where mgr = e.empno);

然而当逻辑被逆向使用,即NOT IN 及NOT EXISTS时,问题就会产生:

selectename from emp where empno not in (select mgr from emp);

selectename from emp e where not exists (select 0 from emp where mgr =

e.empno);

NOT IN语句实质上等同于使用=比较每一值,如果测试为FALSE或者NULL,结果为比较失败。例如:

select 'true' from dual where 1 not in (null,2);

select 'true' from dual where 1 != null and 1 != 2;

select 'true' from dual where (1,2) not in ((2,3),(2,null));

select 'true' from dual where (1,null) not in ((1,2),(2,3));

这些查询不会返回任何一行。第二个查询语句更为明显,即1 != null,所以整个WHERE都为false。然而这些查询语句可变为:

select 'true' from dual where 1 not in (2,3);

select 'true' from dual where 1 != 2 and 1 != 3;

你也可以使用NOT IN查询,只要你保证返回的值不会出现NULL值:

selectename from emp where empno not in (select mgr from emp where mgr is not

null);

selectename from emp where empno not in (select nvl(mgr,0) from emp);

通过理解IN,EXISTS, NOT IN,以及NOT EXISTS之间的差别,当NULL出现在任一子查询中时,你可以避免一些常见的问题。

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