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SQL实现工作日计算_MySQL
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- 2016-06-01 13:44:211507browse
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CREATE FUNCTION Time_Span_of_minutes(
start_day DATETIME,
end_day DATETIME)
RETURNS FLOAT
BEGIN
-- 返回按分钟计算两段时间的间隔，采用逐日靠近的方法求解，一天按8小时480分钟计算，周末不计，不考虑法定节假日。
-- 如果起始日期在周末，则计算当天时间。
DECLARE minutes FLOAT;
DECLARE next_day DATETIME;
SET minutes=0.0;
SET next_day=start_day;
IF(TIMESTAMPDIFF(DAY,start_day,end_day)
SET minutes=minutes+TIMESTAMPDIFF(MINUTE,start_day,end_day);
ELSE
WHILE TIMESTAMPDIFF(DAY,next_day,end_day)>=1.0 DO
IF ((DAYOFWEEK(next_day)=7) OR (DAYOFWEEK(next_day)=1)) THEN
SET next_day=next_day+INTERVAL 1 DAY;
ELSE
SET next_day=next_day+INTERVAL 1 DAY;
SET minutes=minutes+480.0;
END IF;
END WHILE;
SET minutes=minutes+TIMESTAMPDIFF(MINUTE,next_day,end_day);
IF ((DAYOFWEEK(start_day)=7) OR (DAYOFWEEK(start_day)=1)) THEN
SET minutes=minutes+TIMESTAMPDIFF(MINUTE,start_day,CONVERT(CONCAT(SUBSTRING(start_day FROM 1 FOR 10),' 17:30:00'),DATETIME));
END IF;
END IF;
RETURN minutes;
END;
CREATE FUNCTION Time_Span_of_minutes(
start_day DATETIME,
end_day DATETIME)
RETURNS FLOAT
BEGIN
-- 返回按分钟计算两段时间的间隔，采用逐日靠近的方法求解，一天按8小时480分钟计算，周末不计，不考虑法定节假日。
-- 如果起始日期在周末，则计算当天时间。
DECLARE minutes FLOAT;
DECLARE next_day DATETIME;
SET minutes=0.0;
SET next_day=start_day;
IF(TIMESTAMPDIFF(DAY,start_day,end_day)
SET minutes=minutes+TIMESTAMPDIFF(MINUTE,start_day,end_day);
ELSE
WHILE TIMESTAMPDIFF(DAY,next_day,end_day)>=1.0 DO
IF ((DAYOFWEEK(next_day)=7) OR (DAYOFWEEK(next_day)=1)) THEN
SET next_day=next_day+INTERVAL 1 DAY;
ELSE
SET next_day=next_day+INTERVAL 1 DAY;
SET minutes=minutes+480.0;
END IF;
END WHILE;
SET minutes=minutes+TIMESTAMPDIFF(MINUTE,next_day,end_day);
IF ((DAYOFWEEK(start_day)=7) OR (DAYOFWEEK(start_day)=1)) THEN
SET minutes=minutes+TIMESTAMPDIFF(MINUTE,start_day,CONVERT(CONCAT(SUBSTRING(start_day FROM 1 FOR 10),' 17:30:00'),DATETIME));
END IF;
END IF;
RETURN minutes;
END;
没考虑中午休息时间
摘自 Jasper键盘舞步
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