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mysql时间相减的问题_MySQL

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2016-06-01 13:35:191035browse

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mysql时间相减的问题

 

今天看到宁青同学的一条微博,提到mysql日期相减的错误结果,以前没有怎么注意,于是测试了一下,发现确实很坑爹,很容易踩雷,于是整理博客提醒一下大家。

先看一下错误的现象如下,第1条正确,第2,3条的t2-t1不正确:

 

[sql] 

mysql> select t1,t2,t2-t1 from mytest;  

+---------------------+---------------------+-------+  

| t1                  | t2                  | t2-t1 |  

+---------------------+---------------------+-------+  

| 2013-04-21 16:59:33 | 2013-04-21 16:59:43 |    10 |  

| 2013-04-21 16:59:33 | 2013-04-21 17:00:33 |  4100 |  

| 2013-04-21 16:59:33 | 2013-04-21 17:59:35 | 10002 |  

+---------------------+---------------------+-------+  

3 rows in set  

 

全部测试脚本如下:

 

[sql] 

--创建表  

mysql> CREATE TABLE mytest (  

  t1 datetime,  

  t2 datetime  

);  

Query OK, 0 rows affected  

--插入测试记录  

mysql> insert into mytest(t1,t2) values('2013-04-21 16:59:33','2013-04-21 16:59:43');  

Query OK, 1 row affected  

  

mysql> insert into mytest(t1,t2) values('2013-04-21 16:59:33','2013-04-21 17:00:33');  

Query OK, 1 row affected  

  

mysql> insert into mytest(t1,t2) values('2013-04-21 16:59:33','2013-04-21 17:59:35');  

Query OK, 1 row affected  

--验证结果  

mysql> select t1,t2,t2-t1 from mytest;  

+---------------------+---------------------+-------+  

| t1                  | t2                  | t2-t1 |  

+---------------------+---------------------+-------+  

| 2013-04-21 16:59:33 | 2013-04-21 16:59:43 |    10 |  

| 2013-04-21 16:59:33 | 2013-04-21 17:00:33 |  4100 |  

| 2013-04-21 16:59:33 | 2013-04-21 17:59:35 | 10002 |  

+---------------------+---------------------+-------+  

3 rows in set  

 

实际是mysql的时间相减是做了一个隐式转换操作,将时间转换为整数,但并不是用unix_timestamp转换,而是直接把年月日时分秒拼起来,如2013-04-21 16:59:33 直接转换为20130421165933,由于时间不是十进制,所以最后得到的结果没有意义,这也是导致上面出现坑爹的结果。

 

[sql] 

mysql> select t1,  

       t2,  

       convert(t1, UNSIGNED INTEGER) ct1,  

       convert(t2, UNSIGNED INTEGER) ct2,  

       t2-t1,  

       convert(t2, UNSIGNED INTEGER) -convert(t1, UNSIGNED INTEGER) diff0  

  from mytest;   

+-------------------+-------------------+--------------+--------------+-----+-----+  

|t1                 |t2                 |ct1           |ct2           |t2-t1|diff0|  

+-------------------+-------------------+--------------+--------------+-----+-----+  

|2013-04-21 16:59:33|2013-04-21 16:59:43|20130421165933|20130421165943|   10|   10|  

|2013-04-21 16:59:33|2013-04-21 17:00:33|20130421165933|20130421170033| 4100| 4100|  

|2013-04-21 16:59:33|2013-04-21 17:59:35|20130421165933|20130421175935|10002|10002|  

+-------------------+-------------------+--------------+--------------+-----+-----+  

3 rows in set  

 

要得到正确的时间相减秒值,有以下3种方法:

1、time_to_sec(timediff(t2, t1)),

2、timestampdiff(second, t1, t2),

3、unix_timestamp(t2) -unix_timestamp(t1)

 

[sql] 

--测试脚本  

mysql> select t1,  

       t2,  

       t2-t1,  

       time_to_sec(timediff(t2, t1)) diff1,  

       timestampdiff(second, t1, t2) diff2,  

       unix_timestamp(t2) -unix_timestamp(t1) diff3  

  from mytest;  

+---------------------+---------------------+-------+-------+-------+-------+  

| t1                  | t2                  | t2-t1 | diff1 | diff2 | diff3 |  

+---------------------+---------------------+-------+-------+-------+-------+  

| 2013-04-21 16:59:33 | 2013-04-21 16:59:43 |    10 |    10 |    10 |    10 |  

| 2013-04-21 16:59:33 | 2013-04-21 17:00:33 |  4100 |    60 |    60 |    60 |  

| 2013-04-21 16:59:33 | 2013-04-21 17:59:35 | 10002 |  3602 |  3602 |  3602 |  

+---------------------+---------------------+-------+-------+-------+-------+  

3 rows in set  

 

这个问题2003年就有人在mysql4.0的版本时反馈,但mysql官方并不认为是bug,因为他们认为mysql并不支持时间直接相减操作,应该用专用函数处理,所以一直没有修正。但我认为这个很容易导致使用错误,要么就直接报错,要么显示正确的结果。

 

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