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php editor Zimo has a question about safely converting float64 to int64 in Go. We need to consider precision loss and range overflow. In Go, you can use the math package's Round function to round and convert floating point numbers to integers. However, it should be noted that if the floating point number exceeds the range of int64, an overflow error may occur during the conversion process. In order to avoid this situation, we can use the IsNaN function of the math package to check whether the floating point number is NaN, and then convert it to ensure the safety of the conversion. This ensures that precision loss and range overflow problems are avoided during the conversion process.
I know the int()
or int64()
type conversion function provided by Go.
Considering that the maximum representable 64-bit floating point number math.MaxFloat64
is much larger than math.MaxInt64
, is there a safe way to convert int64
to int64
(with truncation,)? A way to trigger an overflow error?
If you are converting (not converting or typecasting) from float64
to int64
, then you can convert the floating point value with Compares the nearest double-precision integer value of math.maxint64
to math.minint64
. These numbers cannot be stored exactly in float64
values, but they will be stored as the next integer value above or below these numbers:
float64(math.MaxInt64) // 9223372036854775808 float64(math.MinInt64) // -9223372036854775808
So as long as your float64
value is between these two values, you know it can be converted to int64
without overflowing.
But please note that if you convert in the other direction, there is no guarantee that float64
can accurately represent all
int64# up to int64 ## value, because double-precision floating-point values contain only 52 bits of precision. In this case you have to check if the
int64 value is between
-1<<53 and
1<<53.
math/big package to handle larger values.
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