I'm trying to find a way to match a pattern with regexp.Regexp
using Go.
The standards of the competition are as follows:
- It must match
FooBar
or its substringFoo
at the beginning of the line, or not match at all. - If matched in #1, any match must be followed by other characters (i.e.
\S
)
So, it should match, for example:
- Matches:
FooABC
- Matches:
FooBarABC
- Does not match:
FooBar
(because there are no other characters after it) - Does not match:
ABC
(because it does not start withFoo
)
I've tried various expressions but can't seem to understand it.
I've found that negative lookahead mode exists in other implementations, but Go doesn't seem to provide it. Is there any other way to solve this problem?
See (updated): https://regex101.com/r/SWSTzv/3
I know this can obviously be solved without using regexp
. However, the purpose of this request is to understand whether this problem can be solved by Go's stdlib implementation.
Correct answer
Why not just reverse the result that matches the regular expression ^Foo(?:Bar)?$
(ok , not just)?
package main import ( "fmt" "regexp" "strings" ) func main() { re := regexp.MustCompile(`^Foo(?:Bar)?$`) str := `Foo FooBar FooA FooB FooBa FooBax FooBxr FooBarAbc FooBarFoo ABC AbcFooBar` for _, s := range strings.Split(str, "\n") { if strings.HasPrefix(s, "Foo") && !re.MatchString(s) { fmt.Println(s) } } }
Output:
<code>FooA FooB FooBa FooBax FooBxr FooBarAbc FooBarFoo </code>
Try it on rextester.
renew
One that is more regular expression based and uses tips em>.
package main import ( "fmt" "regexp" "strings" ) func main() { re := regexp.MustCompile(`^Foo$|^FooBar$|^(Foo.+)`) str := `Foo FooBar FooA FooB FooBa FooBax FooBxr FooBarAbc FooBarFoo ABC AbcFooBar` for _, s := range strings.Split(str, "\n") { submatches := re.FindStringSubmatch(s) if submatches != nil && submatches[1] != "" { fmt.Println(submatches[1]) } } }
Try it on rextester.
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