Home  >  Article  >  Backend Development  >  Close goroutines faster using channels

Close goroutines faster using channels

WBOY
WBOYforward
2024-02-06 09:12:04762browse

使用通道更快地关闭 goroutine

Question content

I am new to GO and I have a question about stopping a goroutine using a channel signal.

I have a long running goroutine (over 1000 of them) and a manager to manage it:

func myThreadFunc(stop chan bool) {
    for {
        select {
        case <- stop:
            log.Debug("Stopping thread")
            return
        default:
            callClientTask() 
        }
    }
}

func callClientTask() {
    // This can take long time up to 30 seconds - this is external HTTP API call
    time.Sleep(5 * time.Second)
}


func manager() {
    var cancelChannelSlice []chan bool
    for i := 0; i < 1000; i++ {
        cancelChannel := make(chan bool)
        cancelChannelSlice = append(cancelChannelSlice, cancelChannel)

        go myThreadFunc(cancelChannel)
    }

    var stopTest = func() {
        for _, c := range cancelChannelSlice {
            c <- true
        }
    }

    timeout := time.After(time.Duration(300) * time.Second)
    for {
        select {
        case <-timeout:
            stopTest()
        default:
            time.Sleep(time.Second)
        }
    }
}

In this case, every time I call c <- true the manager waits for callClientTask() to complete before moving on to the next cancelChannel I want all goroutines to stop in 1 iteration of callClientTask() (no more than 30 seconds)

The only way I tried was to cast the new goroutine like this:

var stopTest = func() {
        for _, c := range cancelChannelSlice {
            go func(c chan bool) {
                c <- true
                close(c)
            }(c)
        }
    }

Am I doing this the right way?


Correct answer


As far as I understand from your question, "You want all goroutines to stop within 1 iteration of callClientTask() (no more than 30 seconds )" and the worker threads run simultaneously without synchronization issues.

I reorganized the code to run concurrently with the wait group.

Sample code:

package main

import (
    "log"
    "sync"
    "time"
)

func worker(stop <-chan struct{}, wg *sync.WaitGroup) {
    defer wg.Done()

    for {
        select {
        case <-stop:
            log.Println("Stopping thread")
            return
        default:
            callClientTask()
        }
    }
}

func callClientTask() {
    time.Sleep(2 * time.Second) // simulate a long-running task (for testing purposes)
}

func main() {
    var wg sync.WaitGroup
    stop := make(chan struct{})

    for i := 0; i < 1000; i++ {
        wg.Add(1)
        go worker(stop, &wg)
    }

    time.Sleep(5 * time.Second) // allow workers to run for a while
    close(stop)                 // stop all workers, close channel
    wg.Wait()                   // wait for all workers
}

Output:

2023/10/26 10:40:44 Stopping thread
2023/10/26 10:40:44 Stopping thread
....
2023/10/26 10:40:49 Stopping thread
2023/10/26 10:40:49 Stopping thread

edit:

If you want to stop some workers, you must update the workers. The following code includes a worker with "stop" and "stop" channels and a start/stop function.

Sample code:

package main

import (
    "log"
    "sync"
    "time"
)

type Worker struct {
    stop    chan struct{}
    stopped chan struct{}
}

func NewWorker() *Worker {
    return &Worker{
        stop:    make(chan struct{}),
        stopped: make(chan struct{}),
    }
}

func (w *Worker) Start(wg *sync.WaitGroup) {
    wg.Add(1)
    go func() {
        defer wg.Done()
        for {
            select {
            case <-w.stop:
                log.Println("Stopping thread")
                close(w.stopped)
                return
            default:
                callClientTask()
            }
        }
    }()
}

func (w *Worker) Stop() {
    close(w.stop)
    <-w.stopped
}

func callClientTask() {
    time.Sleep(2 * time.Second) // simulate a long-running task (for testing purposes)
}

func main() {
    var wg sync.WaitGroup
    workers := make([]*Worker, 1000)

    for i := 0; i < 1000; i++ {
        workers[i] = NewWorker()
        workers[i].Start(&wg)
    }

    time.Sleep(5 * time.Second) // allow workers to run for a while 
    for i := 0; i < 100; i++ { // stop  first 100 workers
        workers[i].Stop()
    }  
    for i := 100; i < 1000; i++ { // wait other workers to finish
        workers[i].Stop()
    }
    wg.Wait()
}

Output:

2023/10/26 12:51:26 Stopping thread
2023/10/26 12:51:28 Stopping thread
2023/10/26 12:51:30 Stopping thread
....

The above is the detailed content of Close goroutines faster using channels. For more information, please follow other related articles on the PHP Chinese website!

Statement:
This article is reproduced at:stackoverflow.com. If there is any infringement, please contact admin@php.cn delete