


matlab calculates the coefficients of the Taylor series expansion of polynomials
clear;clc;
syms x a;
m=5;%Change it yourself
y=(11/6-3*x 3/2*x^2-1/3*x^3)^a
f=taylor(y,m 1,x);
w=sym(zeros(m 1,1));
w(1)=subs(f,x,0);
f=f-w(1);
for n=m:-1:2
w(n 1)=subs(f-subs(f,x^n,0),x^n,1);
f=f-w(n 1)*x^n;
end
w(2)=subs(f,x,1)
Note that because the matlab array subscript starts from 1, here w(1) is a constant term and w(2) is a linear term, so By analogy,
y=w(1) w(2)*x w(3)*x^2 .... w(m 1)*x^m
How to solve the problem of undetermined coefficients in matlab
【1】Transform the function
>>f=sym('2*x^3 3*x^2 21*x 4-(3*a*x^3 b*x^2 c*x d)=0')
f =
2*x^3 3*x^2 21*x 4-(3*a*x^3 b*x^2 c*x d)=0
【2】Use collect to merge similar items
>>ff=collect(f):
(2-3*a)*x^3 (3-b)*x^2 (21-c)*x 4-d = 0
[3] Use maple to extract polynomial coefficients. If there are many, you can use loop statements.
>>c3=maple('coeff',ff,x,3)
c3 =2-3*a
>>c1=maple('coeff',ff,x,1)
c1 =21-c
>>c2=maple('coeff',ff,x,2)
c2 =3-b
>>c0=maple('coeff',ff,x,0)
c0 =4-d
Replenish:
This time it turned out like this, the program worked, but I’m not very satisfied. How about we sort it out together?
syms a b c d x
%【1】Transform the function
f=sym('2*x^3 3*x^2 21*x 4-(3*a*x^3 b*x^2 c*x d)')
N=3;
for i=0:N
temp=maple('coeff',f,x,N-i);
cp(1,i 1)={temp};
end
celldisp(cp);
Additional addition: This time it is finally solved, but it looks very stupid and not very ideal. I just make do with it. Of course, I believe it can be modified to be beautiful.
syms a b c d x
f=sym('2*x^3 3*x^2 21*x 4-(3*a*x^3 b*x^2 c*x d)')
N=3;
for i=0:N
temp=maple('coeff',f,x,N-i);
temp1(i 1)=temp;
end
cp=temp1
a=solve(cp(1)), b=solve(cp(2)), c=solve(cp(3)), d=solve(cp(4))
operation result:
a =2/3
b =3
c =21
d =4
The functional formula M file for the value of polynomial Px anxn an1xn1 a1x a0 is used
First of all, the polynomial is dynamic, so this must be an input term of matlab;
Secondly, the Matlab expression of polynomials must be clear. It is to extract the coefficients of the polynomials after lowering the power to represent the polynomial. The -n degree polynomial of the polynomial is represented by an n 1-dimensional vector; for example, the polynomial 3*x^2 5 in matlab Expressed as [3 0 5];
Finally, you need to understand the matlab method of polynomial function value, which is the command polyval.
Based on the above, the M file is as follows:
function val = fpolyval(p,x)
% Function fpolyval Function: Function value val of polynomial p at x.
% The input item p is the coefficient of the polynomial arranged in descending powers;
val = polyval(p,x);
For example: 3*x^2 5 value at x=1,2
>>p=[3 0 5];
>>x=[1 2];
>>val=fpolyval(p,x)
val =
8 17
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