PHP代码:--------------------------------------------------------------------------------
$sRand = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789';
$length = strlen($sRand);
if (!($dir = @opendir("/dic"))) {
mkdir ("dic", 0777);
}
for ($q=0; $q if ($q > 25 && $q $op = 'cap';
} else {
$op = ';
}
$fp = fopen("./dic/".$op.$sRand[$q].".txt", "w");
$crack = $sRand[$q];
fputs($fp, $crack."|".md5($crack)."\n");
for ($m=0; $m $crack = $sRand[$q].$sRand[$m];
fputs($fp, $crack."|".md5($crack)."\n");
for ($l=0; $l $crack = $sRand[$q].$sRand[$m].$sRand[$l];
fputs($fp, $crack."|".md5($crack)."\n");
for ($o=0; $o $crack = $sRand[$q].$sRand[$m].$sRand[$l].$sRand[$o];
fputs($fp, $crack."|".md5($crack)."\n");
}
}
}
fclose($fp);
}
--------------------------------------------------------------------------------
需要注意地是,这只是一个例子,为了简单期间,我们锁定密码字元为26个小写字母,26个大写字母,10个数字(相信应该适合大多数密码了,不知哪位BT朋友加标点符号呢?呵呵……),而我们只测试四位以内地密码,密码位数增多时原理相同,只是破解可能性大大降低,这个一会儿再讲。
这样,就再dic目录下产生了一系列字典文件。
现在,让我们来做一个MD5的随机密码:
PHP代码:--------------------------------------------------------------------------------
$afcontent = file("./dic/".$op.$sRand[$s].".txt", "r");
foreach($afcontent as $sdics) {
$adics = explode("|", $sdics);
if (substr($adics[1], 0, 32) == $md5_pwd) {
echo "破解密码为:".$adics[0]."
";
$mtime = explode(' ', microtime());
$endtime = $mtime[1] + $mtime[0];
echo "总耗时:".round($endtime - $starttime, 6)."秒
";
echo "继续测试";
exit();
}
}
for ($s=0; $s if ($s >25 && $s $op = 'cap';
} else {
$op = ';
}
$afcontent = file("./dic/".$op.$sRand[$s].".txt", "r");
foreach($afcontent as $sdics) {
if (md5($sdics) == $md5_pwd) {
echo "破解密码为:".$sdics;
exit();
}
}
}
--------------------------------------------------------------------------------
在程序中,你再加上检测运行时间的代码,就可以知道破解一个62字元四位长度的MD5密码需要多长时间了。。。
没测之前,大家先估计一下呢?
还有,现在默认要产生大概537M~~
且需花费15分钟左右生成字典(在我PIII733 256M 内存上)

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