Write a program in C language to check if a given year is a leap year or not

A leap year has 366 days, while an ordinary year has 365 days. The task is to check whether a given year is a leap year through a program.

The logic of judgment can be implemented by checking whether the year is divisible by 400 or 4, but if it is not divisible by these two numbers, it is an ordinary year.

Example

Input-: year=2000
Output-: 2000 is a Leap Year

Input-: year=101
Output-: 101 is not a Leap year

Algorithm

Start
Step 1 -> declare function bool to check if year if a leap year or not
bool check(int year)
   IF year % 400 = 0 || year%4 = 0
      return true
   End
   Else
      return false
   End
Step 2 -> In main()
   Declare variable as int year = 2000
   Set check(year)? printf("%d is a Leap Year",year): printf("%d is not a Leap Year",year)
   Set year = 10
   Set check(year)? printf("%d is a Leap Year",year): printf("</p><p>%d is not a Leap Year",year);
Stop

Example

#include <stdio.h>
#include <stdbool.h>
//bool to check if year if a leap year or not
bool check(int year){
   // If a year is multiple of 400 or multiple of 4 then it is a leap year
   if (year % 400 == 0 || year%4 == 0)
      return true;
   else
      return false;
}
int main(){
   int year = 2000;
   check(year)? printf("%d is a Leap Year",year): printf("%d is not a Leap Year",year);
   year = 101;
   check(year)? printf("%d is a Leap Year",year): printf("</p><p>%d is not a Leap Year",year);
   return 0;
}

Output

2000 is a Leap Year
101 is not a Leap Year

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