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golang implements atoi

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2023-05-19 10:45:08543browse

Golang is a high-level programming language for developing web applications and cloud computing applications. Its syntax is simple and intuitive, with powerful concurrency performance and built-in Garbage Collector. In Golang, the strconv package is often used to process strings. Convert.

When we need to convert a string into an integer, we can use the Atoi function in the strconv package. So, next we will take a look at how to implement the Atoi function in Golang.

The definition of the Atoi function is as follows:

func Atoi(s string) (int, error)

Among them, s represents the string to be converted, and the returned result is an integer of type int and an error value. When the string If it cannot be converted to an integer, an error is returned.

Before introducing the implementation of the Atoi function, we need to first understand several important concepts about strings and integers in Golang: ASCII code, character type and rune type.

First of all, ASCII code is a way of encoding characters. In Golang, each character corresponds to an ASCII code, and this code value ranges from 0 to 255. The character type in Golang is byte type, so a character is actually a byte. We can obtain its ASCII code by coercing a byte type character into an int type.

Secondly, the rune type is a type that can represent Unicode code points. It is an alias of the int32 type. In Golang, a Unicode character may be composed of multiple bytes, so the string is actually composed of rune type characters.

With the above basic knowledge, we can start writing Atoi functions. The following is the code implementation:

package main

import (
    "errors"
)

func Atoi(s string) (int, error) {
    var result int
    var digit int
    var neg bool

    if len(s) == 0 {
        return 0, errors.New("字符串为空")
    }

    if s[0] == '-' {
        neg = true
        s = s[1:]
    }

    for i := 0; i < len(s); i++ {
        digit = int(s[i] - '0')
        if digit < 0 || digit > 9 {
            return 0, errors.New("字符串中包含非数字字符")
        }
        result = result*10 + digit
    }

    if neg {
        result *= -1
    }

    return result, nil
}

func main() {
    i, err := Atoi("123456")
    if err != nil {
        panic(err)
    }
    println(i) // 打印结果 123456

    i, err = Atoi("-123456")
    if err != nil {
        panic(err)
    }
    println(i) // 打印结果 -123456

    _, err = Atoi("")
    if err == nil {
        panic("错误:字符串为空")
    }

    _, err = Atoi("abc123")
    if err == nil {
        panic("错误:字符串中包含非数字字符")
    }
}

In the above code, we first make a non-empty judgment on the input string. If the string is empty, an error is returned; and if the string starts with a negative sign, we Just set its flag to true and remove the negative sign (since we only need to deal with numbers).

Then, we iterate through each character in the string, convert it into a number, multiply it by the corresponding power of 10, and finally add up the result.

Finally, we return the final result based on whether there is a negative sign.

It should be noted that when traversing the string, we need to detect each character to ensure that it only contains numeric characters. If it contains non-numeric characters, we need to return an error.

Through the above code implementation, we can see the simplicity and readability of the Atoi function, which is also one of the major features of the Golang language.

To sum up, the Atoi function in Golang is not very complicated to implement. You only need to understand the basic knowledge and master some programming skills to easily complete this task.

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