golang ip to int

In many computer network programs, we often need to deal with IP addresses. If you are writing a web application using Golang, then you need to know how to convert an IP address into an integer. In this article, we will show how to convert IP address to integer using Golang.

IP Address

An IP address is a unique identifier assigned to a device according to the standard provisions of the Internet Protocol. An IP address consists of 32-bit binary numbers, usually represented by four decimal digits, with each number separated by "." For example, 192.168.0.1 is a common IP address.

In computer networks, IP addresses play an important role in transmitting data. Through the IP address, we can determine the physical location of a device and deliver messages to the correct device.

IP address in Golang

In Golang, IP address is implemented in the net package. Specifically, the net.IP type is a structure representing an IP address. This structure has a series of methods and functions that allow us to process and operate IP addresses.

For example, we can use the net.ParseIP() function to convert an IP address represented by a string into a net.IP instance. The following is a simple example:

import (
    "fmt"
    "net"
)

func main() {
    ipStr := "192.168.0.1"
    ip := net.ParseIP(ipStr)
    fmt.Println(ip)
}

Here, we call the net.ParseIP() function to convert an IP address string into net.IP Example. When the program runs, we will see the following output:

192.168.0.1

Convert IP address to integer

Now we know how to represent IP addresses in Golang. Next, let's look at how to convert an IP address to an integer.

The process of converting an IP address to an integer can be simply described as: converting the four segments of the IP address into hexadecimal and then combining them into an integer.

We can use the net.IP type of method to implement this process. Specifically, net.IP defines a To4() method that converts an IP address into a byte slice of length 4. Each element of this byte slice represents a segment of the IP address.

After getting this byte slice, we use bit operators and shift operators to convert each segment into a hexadecimal number, and then combine these hexadecimal encoded numbers into in an integer. The following is a sample program:

import (
    "fmt"
    "net"
)

func IpToInt(ip net.IP) uint32 {
    ip = ip.To4()
    return uint32(ip[0])<<24 | uint32(ip[1])<<16 | uint32(ip[2])<<8 | uint32(ip[3])
}

func main() {
    ipStr := "192.168.0.1"
    ip := net.ParseIP(ipStr)
    fmt.Printf("%11s: %x
", "IP Address", ip)
    fmt.Printf("%11s: %d
", "Integer", IpToInt(ip))
}

In this sample program, we define a IpToInt() function, which converts the passed IP address into an integer and returns it. This function first extracts a length-4 byte slice from the net.IP object using the To4() method. The values ​​in the bytes are then combined using shift operators to form an integer, and that integer is returned. main() Function Use this function to convert the IP address 192.168.0.1 into an integer and print the result. The output is as follows:

  IP Address: c0a80001
     Integer: 3232235521

Here, c0a80001 is the representation of the IP address in hexadecimal, and 3232235521 is the integer that the IP address is converted into.

Summary

In this article, we introduced how to convert IP address to integer using Golang. We implement this function using net.IP type methods and show specific code examples. I hope this article is helpful to you, thank you for reading!

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