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HomeBackend DevelopmentPHP TutorialExplanation on the solution to the problem of missing double quotes in JSON string key

JSON字符串key缺少引号的解决方法

JSON字符串是key:value形式的字符串,正常key是由双引号括起来的

例如:

<?php
$data = array(&#39;name&#39;=>&#39;fdipzone&#39;);
echo json_encode($data);                        // {"name":"fdipzone"}
print_r(json_decode(json_encode($data), true)); //Array ( [name] => fdipzone )
?>

但如果json字符串的key缺少双引括起来,则json_decode会失败。

<?php
$str = &#39;{"name":"fdipzone"}&#39;;
var_dump(json_decode($str, true)); // array(1) { ["name"]=> string(8) "fdipzone" }
$str1 = &#39;{name:"fdipzone"}&#39;;
var_dump(json_decode($str1, true)); // NULL
?>

解决方法:判断是否存在缺少双引括起来的key,如缺少则先用正则替换为"key",再进行json_decode操作。

<?php
/** 兼容key没有双引括起来的JSON字符串解析
* @param  String  $str JSON字符串
* @param  boolean $mod true:Array,false:Object
* @return Array/Object
*/
function ext_json_decode($str, $mode=false){
    if(preg_match(&#39;/\w:/&#39;, $str)){
        $str = preg_replace(&#39;/(\w+):/is&#39;, &#39;"$1":&#39;, $str);
    }
    return json_decode($str, $mode);
}
$str = &#39;{"name":"fdipzone"}&#39;;
var_dump(ext_json_decode($str, true)); // array(1) { ["name"]=> string(8) "fdipzone" }
$str1 = &#39;{name:"fdipzone"}&#39;;
var_dump(ext_json_decode($str1, true)); // array(1) { ["name"]=> string(8) "fdipzone" }
?>

本文讲解了关于JSON字符串key缺少双引号的解决方法 的讲解,更多相关内容请关注php中文网。

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