How to handle html tag submission failure when Ajax submits parameters

This time I will bring you the html tag when Ajax submits parameters How to handle the submission failure, what are the things to pay attention to when handling the html tag submission failure when handling Ajax submission parameters, the following is the actual combat Let’s take a look at the case.

Recently, I encountered a small problem in the company's resource and article upload function, and I was stuck for a long time.

This function is similar to using rich text

Editor to publish information, but uses Ajax to submit data, so the submitted parameter value inevitably contains html tags.

There has been no problem running the code locally and the submission can always be successful. However, when the code is deployed online, the data cannot be submitted successfully. I was stuck for a long time and it took me a long time to find the problem.

The reason why the submission was unsuccessful is because my submission data contains html tags, and my target address cannot be directly requested.

# Then the solution is as follows:

1. Use JS's base64 coding (similar to encrypted) on the page with the parameter value of HTML tags.

2. After obtaining the data at the target address, use the background Base64 decoding method to decode the obtained data.

The following is the Base64 encoding and decoding method code of my JS:

//下面是64个基本的编码
 var base64EncodeChars = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
 var base64DecodeChars = new Array(
   -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
  -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
  -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, 62, -1, -1, -1, 63,
   52, 53, 54, 55, 56, 57, 58, 59, 60, 61, -1, -1, -1, -1, -1, -1,
   -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14,
   15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, -1, -1, -1, -1, -1,
   -1, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40,
   41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, -1, -1, -1, -1, -1);
 //编码的方法
 function base64encode(str) {
     var out, i, len;
    var c1, c2, c3;
     len = str.length;
    i = 0;
    out = "";
    while(i < len) {
       c1 = str.charCodeAt(i++) & 0xff;
       if(i == len)
       {
             out += base64EncodeChars.charAt(c1 >> 2);
             out += base64EncodeChars.charAt((c1 & 0x3) << 4);
           out += "==";
            break;
          }
      c2 = str.charCodeAt(i++);
       if(i == len)
         {
           out += base64EncodeChars.charAt(c1 >> 2);
            out += base64EncodeChars.charAt(((c1 & 0x3)<< 4) | ((c2 & 0xF0) >> 4));
             out += base64EncodeChars.charAt((c2 & 0xF) << 2);
             out += "=";
            break;
          }
       c3 = str.charCodeAt(i++);
       out += base64EncodeChars.charAt(c1 >> 2);
      out += base64EncodeChars.charAt(((c1 & 0x3)<< 4) | ((c2 & 0xF0) >> 4));
       out += base64EncodeChars.charAt(((c2 & 0xF) << 2) | ((c3 & 0xC0) >>6));
       out += base64EncodeChars.charAt(c3 & 0x3F);
       }
     return out;
   }
 //解码的方法
 function base64decode(str) {
     var c1, c2, c3, c4;
    var i, len, out;
     len = str.length;
     i = 0;
  out = "";
     while(i < len) {
      do {
          c1 = base64DecodeChars[str.charCodeAt(i++) & 0xff];
        } while(i < len && c1 == -1);
       if(c1 == -1)
         break;
      do {
          c2 = base64DecodeChars[str.charCodeAt(i++) & 0xff];
        } while(i < len && c2 == -1);
       if(c2 == -1)
          break;
      out += String.fromCharCode((c1 << 2) | ((c2 & 0x30) >> 4));
      do {
          c3 = str.charCodeAt(i++) & 0xff;
          if(c3 == 61)
            return out;
          c3 = base64DecodeChars[c3];
        } while(i < len && c3 == -1);
       if(c3 == -1)
          break;
       out += String.fromCharCode(((c2 & 0XF) << 4) | ((c3 & 0x3C) >> 2));
     do {
          c4 = str.charCodeAt(i++) & 0xff;
           if(c4 == 61)
            return out;
          c4 = base64DecodeChars[c4];
         } while(i < len && c4 == -1);
      if(c4 == -1)
          break;
       out += String.fromCharCode(((c3 & 0x03) << 6) | c4);
      }
     return out;
   }
 function utf16to8(str) {
     var out, i, len, c;
     out = "";
    len = str.length;
    for(i = 0; i < len; i++) {
      c = str.charCodeAt(i);
      if ((c >= 0x0001) && (c <= 0x007F)) {
          out += str.charAt(i);
        } else if (c > 0x07FF) {
           out += String.fromCharCode(0xE0 | ((c >> 12) & 0x0F));
            out += String.fromCharCode(0x80 | ((c >> 6) & 0x3F));
           out += String.fromCharCode(0x80 | ((c >> 0) & 0x3F));
         } else {
            out += String.fromCharCode(0xC0 | ((c >> 6) & 0x1F));
             out += String.fromCharCode(0x80 | ((c >> 0) & 0x3F));
          }
       }
    return out;
   }
 function utf8to16(str) {
   var out, i, len, c;
    var char2, char3;
    out = "";
    len = str.length;
   i = 0;
    while(i < len) {
     c = str.charCodeAt(i++);
    switch(c >> 4)
       { 
      case 0: case 1: case 2: case 3: case 4: case 5: case 6: case 7:
          // 0xxxxxxx
          out += str.charAt(i-1);
          break;
         case 12: case 13:
          // 110x xxxx  10xx xxxx
          char2 = str.charCodeAt(i++);
         out += String.fromCharCode(((c & 0x1F) << 6) | (char2 & 0x3F));
         break;
        case 14:
         // 1110 xxxx 10xx xxxx 10xx xxxx
         char2 = str.charCodeAt(i++);
          char3 = str.charCodeAt(i++);
           out += String.fromCharCode(((c & 0x0F) << 12) |
                  ((char2 & 0x3F) << 6) |
                  ((char3 & 0x3F) << 0));
          break;
        }
       }
    return out;
  }

The page calls the JS method to perform Base64 encoding code as follows:

 var articleContent = editor.getContent();
   articleContent = base64encode(utf16to8(articleContent));

But, I encountered another one New problem. After using JS to Base64 encode the data, JS actually replaced the plus sign (+) with a space, causing the data decoded by my background method to be incorrect.

The solution is as follows:

I first used the JS method replace() method to replace, but there was an error. JS just replaced my first A space is replaced with a plus sign (+). The final solution is as follows.

In the background (under the target receiving address), replace the spaces with the plus sign (+) for the obtained data. The code is as follows:        

string content = Request["content"].ToString();
      if (content.Contains(""))
        {
          content=content.Replace(" ", "+");
        }
      //byte[] sa = Convert.FromBase64String(content);
      //Encoding Ansi = Encoding.GetEncoding("GB2312");
      // content = Ansi.GetString(sa);
      content = Base64Decrypt(content);//Base64解码

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