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PHP 简单日历实现代码_php技巧

WBOY
WBOYOriginal
2016-05-17 09:29:52942browse
复制代码 代码如下:

$monthoneday=date("Ym")."01";
$oneweekday=date("w",strtotime($monthoneday)); //获得本月1号星期几
$monthday=date("t"); //本月多少天
$startlow=($oneweekday==0)?7:$oneweekday; //从第几列开始

for($a=1,$b=$startlow;$a$ary[$b]=$a; //用数组控制日期在哪里输出
}
$c=1;
//输出行数等于当月天数除7取整再加1
for($a=1;$aecho "";
//我是用数组的key来控制在哪能里输出的
for($b=1;$bif($ary[$c]==date("j")){
echo '';
}else{
echo " ";
}
echo $ary[$c];
echo "";
echo "\n";
}
echo "";
}
?>

写法估计和别人写得不一样...呵...就这点程序我写了半天,刚开始一直是循环思路有问题.居然输出31行1234呵...
看来只有多写才能锻练思维...这个应该用JS实现的,可是我不会JS...只能这样了.

下面是效果...主要是模板挺好看的...

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